我试图学习和理解Rxjs和ngrx / store
我有两个api调用,第一个给我一个字符名称数组,第二个给我一个字符的库存。
如何使用ngrx / store action / reducers / effects在第一个函数返回的数组中运行第二个函数?
这是服务功能:
public getCharacterNames(): Observable<string[]> {
return this._http.get(this._url + '/characters?access_token=' + this._key)
.map((res: Response) => res.json())
.catch((error: any) => Observable.throw(error.json().error || 'server error'));
}
public getCharactersInventory(characterName: string): Observable<Bag[]> {
return this._http.get(this._url + '/characters/' + encodeURI(characterName) + '/inventory?access_token=' + this._key)
.map((res: Response) => res.json())
.catch((error: any) => {return Observable.throw(error.json().error || 'server error'); });
}
这些是行动:
public loadCharacters(): Action {
return {
type: Gw2Actions.LOAD_CHARACTERS
};
}
public loadCharactersSuccess(characters: Character[]) {
return {
type: Gw2Actions.LOAD_CHARACTERS_SUCCESS,
payload: characters
};
}
这是减速器:
case Gw2Actions.LOAD_CHARACTERS_SUCCESS: {
return action.payload;
}
这是我尝试使用的效果:
@Effect() private loadCharacters$: Observable<Action> = this._actions$
.ofType(Gw2Actions.LOAD_CHARACTERS)
.map((action) => action.payload)
.switchMap(() => this._gw2Service.getCharacterNames())
.map((characterNames) => {
let characters = [];
characterNames.forEach((characterName) => {
let characterBags = this._gw2Service.getCharactersInventory(characterName)
.subscribe((res) => res);
characters.push({
name: characterName,
bags: characterBags
});
});
return characters;
}
)
.map((characters: Character[]) => this._gw2Actions.loadCharactersSuccess(characters));
答案 0 :(得分:0)
我建议将Rxjs和ngstore的两个挑战分开。以下是从字符名称解决库存的方法。希望您能够将其映射到您的ngstore效果中。
let charNames$ = Rx.Observable.of([{name: 'a'}, {name: 'b'}, {name: 'c'}]); //mock names
let getInventoryFromName = name => Rx.Observable.of({owner: name}).delay(1000); //mock inventory
let result$ = charNames$.switchMap(names => Rx.Observable.forkJoin(names.map(n => getInventoryFromName(n.name))));
result$.subscribe(res => console.log('got some inventory/user pairs: ', res));
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