Question

我已经有了这段代码

但为此它会产生类似图像[1-10] .jpg的图案但我想要的是像上面这样获取gallley但也喜欢domain.com/gallery/ 我有什么机会让这个工作。

希望有人可以给我打电话。

$parts = preg_split("/\[\d+-\d+\]/", $url, -1, PREG_SPLIT_DELIM_CAPTURE);
preg_match_all("/\[\d+-\d+\]/", $url, $matches, PREG_PATTERN_ORDER);
$parts_number = count($parts);
$matches_number = count($matches[0]);
// JYM
if ($parts_number==1) {

    $image_alt_url=$url;
    $url = str_replace("[", '', $url);
    $url = str_replace("]", '', $url);

    $alto = str_replace("/", '_', $image_alt_url);
    $alto = str_replace("www", '', $alto);
    $alto = str_replace("http", '', $alto);
    $alto = str_replace("https", '', $alto);
    $alto = str_replace("jpg", '', $alto);
    $alto = str_replace("com", '', $alto);
    $alto = str_replace("net", '', $alto);
    $alto = str_replace("info", '', $alto);
    $alto = str_replace(".com.np", '', $alto);
    $alto = str_replace("org", '', $alto);
    $alto = str_replace(".", '', $alto);
    $alto = str_replace(":_", '', $alto);
    $alto = str_replace("-", '_', $alto);
    $alto = preg_replace("/[^a-z-_]/",'',$alto);
    $alto = str_replace("__", '_', $alto);
    $alto = str_replace("___", '_', $alto);
    $alto = str_replace("_", '-', $alto);
    $alto=substr($alto, 1, -1);



    $ary_header = get_headers($url, 1);
    $filesize = $ary_header['Content-Length'];

Answer 1

由于您的问题没有提供任何样本输入，也没有预期的结果，我不得不做出几个假设：

$url="https://www.example.com/gallery/image3.jpg, example.com/gallery/image9.jpg, http://example.com/gallery/image14.JPG";
if(!preg_match_all("/([^, ]*\/)([^,]*?(\d+).jpg)/i",$url,$matches,PREG_SET_ORDER)){
    echo "No Matches Found";
}
foreach($matches as $match){
    list($fullstring,$path,$filename,$id)=$match;
    echo "<div>fullstring=$fullstring</div>";
    echo "<div>path=$path</div>";
    echo "<div>filename=$filename</div>";
    echo "<div>id=$id</div><br>";

    // ...now do any necessary substring processing.
}

输出：

fullstring=https://www.example.com/gallery/image3.jpg
path=https://www.example.com/gallery/
filename=image3.jpg
id=3

fullstring=example.com/gallery/image9.jpg
path=example.com/gallery/
filename=image9.jpg
id=9

fullstring=http://example.com/gallery/image14.JPG
path=http://example.com/gallery/
filename=image14.JPG
id=14

通过隔离您希望保留的字符串部分，您可以减少str_replace() / preg_replace工作量。

如何在没有范围的情况下捕获图像库

1 个答案: