我有一个提到过的吼叫你能不能让我知道如何在这个json中解析Tripname
我想要
增量 宝宝 蓝湾 whaynle
来自json的
MyJson
[{"0":"$deta","Tripname":"delta"},{"0":"Baby","Tripname":"Baby"},{"0":"bluebay","Tripname":"bluebay"},{"0":"whaynle","Tripname":"whaynle"}]
System.out.println("--RESULT--" + result);
JSONObject jObject = null;
try {
jObject = new JSONObject(result);
//JSONArray a = jObject.getJSONArray("Tripname");
String status = jObject.getString("Tripname");
//Log.v("result1", jObject.toString());
Log.v("Response", status);
}
catch (JSONException e)
{
e.printStackTrace();
}
答案 0 :(得分:3)
试试这个:
typedef struct {
double a;
double b;
double c;
unsigned int d;
unsigned int e;
} mystruct;
mystruct m = { 2.333, 4.478, 2.447, 90, 43 };
printf("%.3f %.3f %.3f %u %u\n", m.a, m.b, m.c, m.d, m.e);
答案 1 :(得分:2)
这样做
Connection.Dispose()