Question

我无法想到一个可行的解决方案，可以在餐厅的菜单页面为每个课程创建PHP模板的交替部分。我想创建一个可以实现这个结果的模板：

<section class="well well__off1>
<div>Starters</div>
.... menu list ...
</section>

<section class="bg-secondary well well__off1>
<div>Mains</div>
.... menu list ...
</section>

<section class="well well__off1>
<div>Steaks</div>
.... menu list ...
</section>

etc
etc

我正在运行的当前模板是这样的。如何为每个课程替换CSS部分？

<section class="well well__off1">
    <div class="grid_8">
      <?php foreach ($MDayMeals as $courses => $meals): ?>
      <h4><?php echo $courses; ?></h4>
      <?php foreach ($meals as $meal): ?> 
        <div class="name-wrap">
         <?php echo htmlencode($meal['name_of_dish']) ?>
        </div>
          <?php endforeach ?> 
        <?php endforeach ?>
        </div>
    </div>
</section>

有关如何实现这一目标的任何想法？

由于特里

Answer 1

var user = UserManager.FindById(User.Identity.GetUserId());

Answer 2

希望这有帮助：

  <?php foreach ($MDayMeals as $courses => $meals): ?>
    <?php if($i%2===0): //check value odd or even 
    ?>
  <section class="well well__off1">
<?php else:?>
  <section class="bg-secondary well well__off1">
<?php endif;?>
  <div class="grid_8">
  <h4><?php echo $courses; ?></h4>
  <?php foreach ($meals as $meal): ?> 
    <div class="name-wrap">
     <?php echo htmlencode($meal['name_of_dish']) ?>

    </div>
      <?php endforeach ?> 
       </div>
  </section>
  <?php $i++; ?>
    <?php endforeach ?>

需要一个解决部分的解决方案

2 个答案: