Question

这是我的HTML

<div class="row">
    <div class="form-group">
        <label class="control-label col-sm-3"><font color="#FF0000">*</font><strong>Captcha</strong>
        </label>
        <div class="col-sm-3">
            <?php echo '<img src="captcha.php" alt="captcha">'; ?>
            <br/>
            <span><input name="captcha_entered" type="text"  class="form-control" id="captcha_entered" size="27" maxlength="4"/></br></span>
            <input type="hidden" name="captcha_total" id="captcha_total" value="<?php echo $_SESSION['rand_code']; ?>">
        </div>
    </div>
</div>
<div>&nbsp;</div>
<div class="row">
    <div class="col-sm-12">
        <center>
            <script type="text/javascript">
                document.write("<input type=\"submit\" value=\"Submit\" class=\"btn1\"/>");
            </script>
            <noscript>
                <p style="color: red;"><b><i>Please enable JavaScript to continue</i></b>
                    <p>
            </noscript>
        </center>
    </div>
</div>

这是我的javascript

function q_form_val() {
    var patt = new RegExp(/^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$/);
    var captcha_entered = document.getElementById("captcha_entered").value;
    if (captcha_entered == "") {
        alert("Please enter the Captcha");
        return false;
    }else if(!patt.test(captcha_entered)){
        alert("Bad Captcha Match");
        return false;
    }
    return true;
}

它还为正确的验证码和错误的验证码显示相同的弹出消息。错误和严格的验证码显示与错误的验证码相同的错误。

右侧验证码有什么问题？验证有什么问题？

Answer 1

从中获得帮助。它会解决你的问题。明智地使用它

function myself() {
    this.g = "";
    this.h = [];
    this.i = {};
    myself.prototype = new parent();
    myself.prototype.constructor = myself;
}

function parent() {
    this.d = "";
    this.e = [];
    this.f = {};
    parent.prototype = new grandParent();
    parent.prototype.constructor = parent;
}

function grandParent() {
    this.a = "";
    this.b = [];
    this.c = {};
}

var data = new myself();
var jsonData = {};
do {
    for(var key in data) {
        if(data.hasOwnProperty(key) && data.propertyIsEnumerable(key)) {
            jsonData[key] = data[key];
        }
    }
    data = Object.getPrototypeOf(data).constructor.prototype;
    Object.defineProperties(data, {
        'constructor': {
            enumerable: false
        }
    });
} while (data.constructor.name !== "grandParent")
console.log(jsonData);

我的验证码正在检查它是空还是错，但它没有检查是否正确

1 个答案: