Question

为什么if then语句不能在这里工作

declare @num integer(2);
set @num = 10;

begin
    if (@num < 10)
    Then
        print('hello');

    set @num = @num +1 ;

    else
        print('over');

    set @num = @num +1 ;
    END IF;
END;

我收到这些错误：

第15行，第15行，第1行，第9行   关键字＆＃39;然后＆＃39;附近的语法不正确。

Msg 102，Level 15，State 1，Line 12
  关键字＆＃39; else＆＃39;附近的语法不正确。

Answer 1

试试这个：

 declare @num int;
 set @num = 10;

 if (@num < 10)
 begin
   print('hello');
   set @num = @num +1;
 end
 else 
    begin
      print('over');
      set @num = @num +1;
    end

Answer 2

How many teams do you have to enter?  2
Team 1 City:  Boston
Team 1 Name:  Bruins
Team 2 City:  Toronto
Team 2 Name:  Maple Leafs
City: Boston | Team: Bruins
City: Toronto | Team: Maple Leafs
The last team entered was: Toronto Maple Leafs

如果然后在SQL中声明

2 个答案: