Question

如何从数组中提取值，就像使用.map一样？这是我的代码：

counter = 0
ary = Array.new

puts "How many teams do you have to enter?"
hm = gets.to_i

until counter == hm do
  puts "Team City"
  city = gets.chomp

  puts "Team Name"
  team = gets.chomp

  ary.push([city, team])
  counter += 1
end

ary.map { |x, y|
  puts "City: #{x} | Team: #{y}"
}

print "The last team entered was: "
ary.last

最终结果如下：

City: Boston | Team: Bruins
City: Toronto | Team: Maple Leafs
The last team entered was: 
=> ["Toronto", "Maple Leafs"]

但我想要最后一行阅读

The last team entered was: Toronto Maple Leafs

如何在没有=＆gt;，括号和引号的情况下获取该行的值？

Answer 1

基本上，你提出的问题是“如何将字符串数组元素连接成一个字符串”，Array#join来拯救：

["Toronto", "Maple Leafs"].join(' ')
#⇒ "Toronto Maple Leafs"

Answer 2

使用*的替代方法：

puts ["Toronto", "Maple Leafs"] * ', '
#Toronto, Maple Leafs
#=> nil

但我认为没有人使用这种表示法，因此在另一个答案中建议使用join。

Answer 3

如果您不想在行尾添加换行符，例如获取用户输入时，请使用print代替puts，此外，您还可以使用__cdecl在同一行内打印提出：

#{variable}

使用示例：

counter = 0
ary = Array.new

print "How many teams do you have to enter? "
hm = gets.to_i

until counter == hm do
  print "Team #{counter + 1} City: "
  city = gets.chomp

  print "Team #{counter + 1} Name: "
  team = gets.chomp

  ary.push([city, team])
  counter += 1
end

ary.map { |x, y| puts "City: #{x} | Team: #{y}" }

puts "The last team entered was: #{ary.last.join(' ')}"

试试here!

Answer 4

试一试：

team_last = ary.last
puts "The last team entered was:" + team_last[0] + team_last[1]

Answer 5

根据你的代码ary.last本身返回一个数组，所以首先需要通过ary.last.join(' ')连接数组中的两个元素将其转换为字符串，然后你必须用您的消息字符串即"The last team entered was: #{ary.last.join(' ')}"

代码的最后两行将更改为：

print "The last team entered was: #{ary.last.join(' ')}"

如何在Ruby中获取数组的最后元素？

5 个答案: