Question

我尝试在Node下获取文字和ID，请参阅此处的示例文件：example.xml

但是，它没有像普通XML文件那样的结构。结构如下：

<TextWithNodes><Node id="0"/>
<Node id="1"/>
<Node id="2"/>9407011<Node id="9"/>
<Node id="10"/>ACL<Node id="13"/> <Node id="14"/>1994<Node id="18"/>
<Node id="19"/> Lg.Pr.Dc <Node id="29"/>

我想要的输出是start_node，end_node和text_between_node的列表。我不确定我是否可以使用lxml库来执行此操作。

目前，我使用

from lxml import etree
tree = etree.parse('9407011.az-scixml.xml')
nodes = tree.xpath('//TextWithNodes')[0].getchildren()
node = nodes[0] # example one node
print(node.text) # this give empty string because you don't have closing same id

Answer 1

使用XPath可能对您有用。将from lxml import etree as ET root = ET.XML(b'''<?xml version='1.0' encoding='UTF-8'?> <GateDocument version="3"> <TextWithNodes><Node id="0"/> <Node id="1"/> <Node id="2"/>9407011<Node id="9"/> <Node id="10"/>ACL<Node id="13"/> <Node id="14"/>1994<Node id="18"/> <Node id="19"/> Lg.Pr.Dc <Node id="29"/> </TextWithNodes></GateDocument>''') # Grab each 'Node' element: # Only if the element has an 'id' attribute, and only if # the first sibling is a text node that isn't # all wihtespace and only if # the second sibling is a 'Node' with an 'id' for r in root.xpath('''//Node[@id] [following-sibling::node() [1] [self::text()] [normalize-space() != ""]] [following-sibling::node() [2] [self::Node[@id]]]'''): # All elements that satisfy that above XPath should # also satisfy the requirements for the next line print (r.get('id'), repr(r.tail), r.getnext().get('id'))与空字符串进行比较将消除没有后续文本的节点。

这可能对您有用：

{{1}}

lxml Python，读取给定XML文件结构的文本和树

1 个答案: