Question

儿童班：

using System;
using System.Collections;
namespace Game
{
    public class Warrior:Inhabitant
    {
        public Warrior(string name,int age):base(name,age)
        {
            private bool mobility;
            private bool immortality;
        }
    }
}

现在是父类：

public class Inhabitant {

     private string name;
     private int age;

    public Inhabitant(string name,int age){
        this.name = name;
        this.age = age;
    }

此代码适用于Java。我不明白为什么它不在这里工作。

Answer 1

您需要声明私有字段并在构造函数

中初始化它们

using System;
using System.Collections;
namespace Game
{
    public class Warrior:Inhabitant
    {
        // declare private fields
        private bool mobility;
        private bool immortality;

        public Warrior(string name,int age, bool mobility, bool immortality):base(name,age)
        {
            // initialize
            this.mobility=mobility;
            this.immortality=immortality;
        }
    }
}

Answer 2

声明你的成员在之外的构造函数：

public class Warrior:Inhabitant
{
    private bool mobility;
    private bool immortality;

    // ...
}

将参数传递给新构造函数：

public class Warrior:Inhabitant
{
    private bool mobility;
    private bool immortality;

    public Warrior(string name,int age, bool mobility, bool immortablity) : base(name,age) // base call as usual
    {
        // set properties
        this.mobility = mobility;
        this.immortability = immortability;
    }
}

Answer 3

首先，您不能将任何变量声明为私有内部构造函数或类的方法。

更改Warrior类如下，它应解决问题。

public class Warrior:Inhabitant
{
    private bool mobility;
    private bool immortality;
    public Warrior(string name,int age):base(name,age)
    {

    }
}

如果它们是构造函数的局部变量，那么应该声明它们没有访问修饰符。

public class Warrior:Inhabitant
{
    public Warrior(string name,int age):base(name,age)
    {
        bool mobility;
        bool immortality;
    }
}

Answer 4

你不能在构造函数中使用访问修饰符。尝试：

public Warrior(string name,int age):base(name,age)
{
   bool mobility;
   bool immortality;
}

以上语法是正确的，但在语义上没有做任何事情，因为移动性和不朽性只存在于构造函数中。可能你想要像：

public class Warrior:Inhabitant
{
       private bool mobility;
       private bool immortality;
       public Warrior(string name,int age):base(name,age)
       {
            this.mobility=false; //example case
            this.immortality=true; //example case
       }
}

如何在将参数传递给父类构造函数时向子类构造函数添加更多代码？

4 个答案: