我在通过Safari链接打开我的应用时遇到问题(稍后它将来自我自己的应用)
如果应用程序已打开,则没有问题。如果应用程序未打开,则在通过URL打开时会崩溃。我了解到这是因为我在Appdelegate中调用了两种不同的方法 - didFinishLaunchingWithOptions
和open url
当应用程序打开时我打开打开的网址没有问题,但是如果我在关闭的应用程序上打开网址,应用程序崩溃了。我已经知道didFinishLauchingWithOptions
中的url参数可能为null,但是你如何测试呢。当我在模拟器和iPad上关闭应用程序XCode终止连接
编辑 - 现在能够在Sachin Vas发表评论之后进行调试。 在XCode调试中获取此信息 - 但无法扩展有效负载
我的功能看起来像这样
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
self.window = UIWindow(frame: UIScreen.main.bounds)
let storyBoard : UIStoryboard = UIStoryboard(name: "Main", bundle:nil)
let nav = storyBoard.instantiateViewController(withIdentifier: "HomeNavController") as! UINavigationController
let home = storyBoard.instantiateViewController(withIdentifier: "HomeViewController") as! HomeViewController
if let url = launchOptions?[UIApplicationLaunchOptionsKey.url] as? NSURL {
if let itemid = getQueryStringParameter(url: url.absoluteString!, param: "itemid"){
NetworkService().getSpecificExercise(id: itemid) { response, error in
let exercise = response! as VoiceExercise
let vc = storyBoard.instantiateViewController(withIdentifier: "ExerciseViewController") as! ExerciseViewController
vc.exercise = exercise
switch exercise.type {
case "STRENGTH":
vc.exercisetype = .strength
case "RANGE":
vc.exercisetype = .range
case "COMBINED":
vc.exercisetype = .combined
default:
print(exercise.type)
}
nav.pushViewController(vc, animated: false)
self.window?.rootViewController = nav
//self.window?.makeKeyAndVisible()
}
return true
}
}else{
//nav.pushViewController(home, animated: true)
self.window?.rootViewController = home
self.window?.makeKeyAndVisible()
}
nav.pushViewController(home, animated: true)
self.window?.rootViewController = nav
self.window?.makeKeyAndVisible()
return true
}
func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
if let itemid = getQueryStringParameter(url: url.absoluteString, param: "itemid"){
NetworkService().getSpecificExercise(id: itemid) { response, error in
let exercise = response! as VoiceExercise
let vc = storyBoard.instantiateViewController(withIdentifier: "ExerciseViewController") as! ExerciseViewController
vc.exercise = exercise
switch exercise.type {
case "STRENGTH":
vc.exercisetype = .strength
case "RANGE":
vc.exercisetype = .range
case "COMBINED":
vc.exercisetype = .combined
default:
print(exercise.type)
}
self.window?.rootViewController = vc
self.window?.makeKeyAndVisible()
}
return true
}else{
return false
}
}
答案 0 :(得分:2)
您可以检查网址的主机是否为空,如果是,请查看以下网址
if url.host == nil
{
return true;
}
if let sUrl = url
{
urlString = url.absoluteString
}
希望它有所帮助!
<强>已更新强>
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
if let launchOptions = launchOptions {
if #available(iOS 9.0, *) {
if let url = launchOptions[UIApplicationLaunchOptionsKey.url] as? UIApplicationShortcutItem {
print("url: \(url)")
}
}
}
return true
}