我正在尝试创建一个用户可以登录和注销的应用程序 当他们登录时,会向他们显示一个活动,显示他们的电子邮件和姓名(来自数据库)。
我最近添加了一个导航栏选项。当用户进入导航栏并选择一个页面(关于,设置等)时,他们将转到该活动。如果按下后退按钮转到登录的Activity(LoginSuccess.java),应用程序崩溃显示"不幸的是,Frienday已停止运行。"
我试图调试它,它导致我在LoginSuccess.java中出现NullPointerException。我尝试删除LoginSuccess.java文件中的项目,这些项目会显示用户的姓名和电子邮件。如果删除这些,后退按钮将正常工作。
LoginSuccess.java文件
TextView name, email;
protected void onCreate(Bundle savedInstanceState) {
...
name = (TextView) findViewById(R.id.name);
email = (TextView) findViewById(R.id.name);
Bundle bundle = getIntent().getExtras();
name.setText(bundle.getString("name"));
email.setText("Email: " + bundle.getString("email"));
}
login.php文件(用于数据库)
<?php
require "init.php";
$user_name = $_POST["user_name"];
$password = $_POST["password"];
$sql = "SELECT name,email FROM user_info WHERE user_name LIKE '".$user_name."' AND password LIKE '".$password."';";
$result = mysqli_query($con, $sql);
$response = array();
# Check if user already exists.
if (mysqli_num_rows($result) > 0)
{
$row = mysqli_fetch_row($result);
$name = $row[0];
$email = $row[1];
$code = "login_success";
array_push($response, array ("code" => $code, "name" => $name, "email" => $email));
echo json_encode($response);
}
else
{
$code = "login_failed";
$message = "User not found... Please try again!";
array_push($response, array("code" => $code, "message" => $message));
echo json_encode($response);
}
mysqli_close($con);
?>
logcat的
E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.goril.friendays, PID: 32166
java.lang.RuntimeException: Unable to start activity ComponentInfo{com.goril.friendays/com.goril.friendays.LoginSuccess}: java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String android.os.Bundle.getString(java.lang.String)' on a null object reference
at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:3254)
at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:3350)
at android.app.ActivityThread.access$1100(ActivityThread.java:222)
at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1795)
at android.os.Handler.dispatchMessage(Handler.java:102)
at android.os.Looper.loop(Looper.java:158)
at android.app.ActivityThread.main(ActivityThread.java:7237)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1230)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1120)
Caused by: java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String android.os.Bundle.getString(java.lang.String)' on a null object reference
at com.goril.friendays.LoginSuccess.onCreate(LoginSuccess.java:25)
at android.app.Activity.performCreate(Activity.java:6876)
at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1135)
at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:3207)
at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:3350)
at android.app.ActivityThread.access$1100(ActivityThread.java:222)
at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1795)
at android.os.Handler.dispatchMessage(Handler.java:102)
at android.os.Looper.loop(Looper.java:158)
at android.app.ActivityThread.main(ActivityThread.java:7237)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1230)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1120)
我几天都在努力解决这个问题。如果有人可以帮助我,我很乐意欣赏它:)。我在Android网站教程中实现了后退选项。
教程: https://developer.android.com/training/implementing-navigation/ancestral.html
答案 0 :(得分:1)
当您按下时,getIntent()
不存在于上一个启动该活动的活动中,因此它将为空。
你可以这样抓住
Bundle extras = getIntent().getExtras();
if (extras != null) {
name.setText(bundle.getString("name"));
email.setText("Email: " + bundle.getString("email"));
}
答案 1 :(得分:0)
我想你已经有了解释, 试着读一下:
Caused by: java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String android.os.Bundle.getString(java.lang.String)' on a null object reference
bundle是null,你试图在null对象上获取一个字符串。 你需要检查是否为空。