Question

所以我有几张桌子：

___ TABLE A (users info) ___
team_id | user_id | points | rewards

___ TABLE B (points for every event)___
team_id | user_id | points | rewards | event_type

___ Table C (users) ___
user_id | name | etc..

在表A中，我有基于团队的所有用户的摘要信息。在表B中，我有每个事件的原子信息（类似于历史）。我想仅使用user_id通过表B中的某些相同字段更新表A（点和奖励）中的信息。我的问题是我无法理解如何在一个查询中执行此操作。

例如，我可以进行类似

的查询

WITH storage as (
    SELECT
        sum(points) as points,
        sum(rewards) as rewards,
        team_id FROM B
    WHERE user_id = 1 AND team_id = 1
)

UPDATE A
SET
   points = (
      SELECT points FROM storage
),
   rewards = (
      SELECT rewards FROM storage)
WHERE user_id = 1 and team_id = 1 ;

但我想在没有team_id的情况下运行此操作。例如，我运行像

这样的sql

WITH storage as (
    SELECT
        sum(points) as points,
        sum(rewards) as rewards,
        team_id FROM B
    WHERE user_id = 1 GROUP BY team_id
)

在此更新之后，基于team_id为表B中的每一行指出并奖励。是否可以在后端进行无循环查询？的更新： 它适用于SQLite数据库 更新2 您可以找到回复enter link description here

Answer 1

喜欢这个吗？

update A set A.points = B.sumpoints, A.reward = B.sumreward 
from A, 
  (select userid, teamid, sum(points) sumpoints, sum(reward) sumreward 
   from B group by userid, teamid) B 
where A.userid = B.userid and A.teamid = B.teamid

Answer 2

所以最后我找到了SQLite的解决方案。它非常接近我的第一个查询。

WITH storage as (
    SELECT
        sum(points) as points,
        sum(rewards) as rewards,
        team_id FROM B
    WHERE team_id IS NOT NULL AND user_id = 1
    GROUP BY team_id
)

UPDATE A
SET
   points = (
      SELECT points FROM storage WHERE storage.team_id = A.team_id
),
   rewards = (
      SELECT rewards FROM storage WHERE storage.team_id = A.team_id
)
WHERE user_id = 1;

还可以删除未使用的数据以将where语句添加到WITH存储块（通过user_id添加过滤器）

(sales, sales.map

基于另一个表

2 个答案: