我有代码
let dirtyHtml = `<img class="emojione" src="">
<img class="a" src="edw">
<img class="emojione" src="" />
<img class="emojione" src=""/>
<img src="">`;
let clearHtml = dirtyHtml.replace(/<img[^<>]+(?!emojione)[^<>]+>/gi, '');
console.log(clearHtml);
我希望看到这个
<img class="emojione" src="">
<img class="emojione" src="" />
<img class="emojione" src=""/>
但我会看到空字符串......
我的正则表达式出了什么问题?
答案 0 :(得分:2)
/<img(?:(?!emojione).)*>/gi
将匹配<img
和>
之间不包含字符串emojione
的任何内容。像这样:
let dirtyHtml = `<img class="emojione" src="">
<img class="a" src="edw">
<img class="emojione" src="" />
<img class="emojione" src=""/>
<img src="">`;
let clearHtml = dirtyHtml.replace(/<img(?:(?!emojione).)*>/gi, '');
console.log(clearHtml);
&#13;
答案 1 :(得分:0)
您可以尝试这一点(img
[a-z]{3}
是否重要,因为src
支持的元素更多而不是3个字符http://www.w3resource.com/html/attributes/html-src-attribute.php,但写img
)
let dirtyHtml = `<img class="emojione" src="">
<img class="a" src="edw">
<img class="emojione" src="" />
<img class="emojione" src=""/>
<img src="">`;
let clearHtml = dirtyHtml.replace(/(<img class="[a-z]?" src="[a-z]+">)|(<img src="">)/gi, '');
console.log(clearHtml);
&#13;
答案 2 :(得分:0)
我不会重复很多reasons为什么RegExp用于修改HTML是一个坏主意(并且被许多人视为黑客攻击),但我想表明使用是多么自然jQuery 执行此任务
let dirtyHtml = `<img class="emojione" src="">
<img class="a" src="edw">
<img class="emojione" src="" />
<img class="emojione" src=""/>
<img src="">`;
// Put your html string within some HTML element to make a starting point
var $wrap = $('<div/>').append(dirtyHtml);
// Remove image tags without specific class
$wrap.find('img:not(.emojione)').remove();
console.log($wrap.html())
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>