我正在使用PortalId
。我试图在我的代码中添加Selenium Standalone Server 3.0.1
,以便在元素变得可见时通过xpath检测元素。为了获得一些Java帮助,我查找了Explicit Wait
的源代码,但无法找到它。我在Selenium Standalone Server 3.0.1
版本中找到了源代码。我下载了它并找到selenium-java-2.53.1
并添加到我的selenium-java-2.53.1-srcs
。在Eclipse IDE
的帮助下,我只需复制粘贴我FluentWait
中的代码并更改变量名称。
文档中的示例代码如下:
Eclipse IDE
但是当我实现这段代码时,只需复制粘贴它:
// Waiting 30 seconds for an element to be present on the page, checking
// for its presence once every 5 seconds.
Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
.withTimeout(30, SECONDS)
.pollingEvery(5, SECONDS)
.ignoring(NoSuchElementException.class);
WebElement foo = wait.until(new Function<WebDriver, WebElement>() {
public WebElement apply(WebDriver driver) {
return driver.findElement(By.id("foo"));
}
});
我在 Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
.withTimeout(30, TimeUnit.SECONDS)
.pollingEvery(5, TimeUnit.SECONDS)
.ignoring(NoSuchElementException.class);
WebElement element = wait.until(new Function<WebDriver, WebElement>() {
public WebElement apply(WebDriver driver) {
return driver.findElement(By.xpath("//p[text()='WebDriver']"));
}
});
类上收到FluentWait
以下是我的导入列表:
The type FluentWait is not generic; it cannot be parameterized with arguments <WebDriver>
有人可以帮帮我吗?
在 Selenium v3.11.0
中添加了关于 FluentWait 的修改构造函数的answer答案 0 :(得分:3)
随着 Selenium v3.11.0 的推出,FluentWait的构造函数发生了变化。现在 withTimeout 和 pollingEvery 的参数类型为Duration。以下是修改后的实现:
import java.time.Duration;
import org.openqa.selenium.By;
import org.openqa.selenium.NoSuchElementException;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;
import org.openqa.selenium.support.ui.FluentWait;
import org.openqa.selenium.support.ui.Wait;
import com.google.common.base.Function;
public class Fluent_Wait {
public static void main(String[] args) {
System.setProperty("webdriver.gecko.driver", "C:\\Utility\\BrowserDrivers\\geckodriver.exe");
WebDriver driver = new FirefoxDriver();
driver.get("https://www.google.com");
// Waiting 30 seconds for an element to be present on the page, checking
// for its presence once every 500 milliseconds.
Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
.withTimeout(Duration.ofSeconds(30))
.pollingEvery(Duration.ofMillis(500))
.ignoring(NoSuchElementException.class);
WebElement foo = wait.until(new Function<WebDriver, WebElement>() {
public WebElement apply(WebDriver driver) {
return driver.findElement(By.name("q"));
}
});
}
}
答案 1 :(得分:2)
我也遇到了同样的错误,后来我注意到我使用的类名是 fluentwait
。更改类名后,它工作正常。
答案 2 :(得分:1)
您需要在等待中指定预期条件,这是可以解决您问题的修改后的代码。
代码:
import java.util.concurrent.TimeUnit;
import org.junit.Test;
import org.openqa.selenium.By;
import org.openqa.selenium.NoSuchElementException;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.support.ui.ExpectedConditions;
import org.openqa.selenium.support.ui.FluentWait;
import org.openqa.selenium.support.ui.Wait;
public class DummyClass
{
WebDriver driver;
@Test
public void test()
{
Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
.withTimeout(30, TimeUnit.SECONDS)
.pollingEvery(5, TimeUnit.SECONDS)
.ignoring(NoSuchElementException.class);
until(new Function<WebElement, Boolean>()
{
public Boolean apply(WebElement element)
{
return element.getText().endsWith("04");
}
private void until(Function<WebElement, Boolean> function)
{
driver.findElement(By.linkText("Sample Post2"));
}
}
}
}
答案 3 :(得分:0)
最简单的解决方案是使用其他方法实现:
withTimeout(Duration.ofSeconds(10))
.pollingEvery(Duration.ofSeconds(2))
表格withTimeout(Duration timeOut)
仍在使用且不推荐使用