我有一个可以点击的按钮,它会打开一个带有一个文本字段的弹出框。每当我输入内容并单击“添加”时,我希望将其插入到我的数据库中。
目前,当我点击“添加”时,它会插入到数据库中,但它不会读取输入的值。因此,只需输入空值。我没有收到任何可以看到的错误,但是在我的JavaScript中我执行console.log(type + " : " + value);
并在日志中返回sku_group-0 :
。我也做console.log(dict)
,日志中的输出是Object {}
,因此看起来输入的值不会被记录。我也在日志中收到一条成功的row inserted
消息,所以我肯定认为这只是能够读取值的问题。
所以我的问题是如何让它读取值并成功将其输入数据库。
添加按钮的HTML:
<button class="create-user" id="insertButton">Add Group</button>
弹出框的HTML:
<div id="dialog-form" title="Add Group">
<p class="validateTips">Please Add a Group</p>
<!-- Dialog box displayed after add row button is clicked -->
<form>
<fieldset>
<label for="sku_group">SKU Group</label>
<input type="text" name="group" id="group" class="text ui-widget-content ui-corner-all">
<!-- Allow form submission with keyboard without duplicating the dialog button -->
<input type="submit" id="submit" tabindex="-1" style="position:absolute; top:-1000px">
</fieldset>
</form>
</div>
JavaScript的:
$( function() {
var dialog, form,
sku_group = $( "#group" ),
allFields = $( [] ).add( sku_group ),
tips = $( ".validateTips" );
console.log(allFields);
function updateTips( t ) {
tips
.text( t )
.addClass( "ui-state-highlight" );
setTimeout(function() {
tips.removeClass( "ui-state-highlight", 1500 );
}, 500 );
}
function checkRegexp( o, regexp, n ) {
if ( !( regexp.test( o.val() ) ) ) {
o.addClass( "ui-state-error" );
updateTips( n );
return false;
} else {
return true;
}
}
function addGroup() {
var valid = true;
allFields.removeClass( "ui-state-error" );
// ----- Validation for each input in add row dialog box -----
valid = valid && checkRegexp( sku_group, /^[a-z]([0-9a-z_\s])+$/i, "Please enter a valid SKU Group name" );
console.log(allFields);
if ( valid ) {
var $tr = $( "#skuTable tbody tr td" ).eq(0).clone();
var dict = {};
var errors = "";
$tr.each(function(){
var type = $(this).attr('id');
var value = $(this).html();
console.log(type + " : " + value);
switch (type) {
case "group":
dict["SKU Group"] = value;
break;
}
});
$( "#skuTable tbody" ).append($tr);
dialog.dialog( "close" );
console.log(dict);
var request = $.ajax({
type: "POST",
url: "insert-group.php",
data: dict
});
request.done(function (response, textStatus, jqXHR){
if(JSON.parse(response) == true){
console.log("row inserted");
} else {
console.log("row failed to insert");
console.log(response);
}
});
// Callback handler that will be called on failure
request.fail(function (jqXHR, textStatus, errorThrown){
console.error(
"The following error occurred: "+
textStatus, errorThrown
);
});
// Callback handler that will be called regardless
// if the request failed or succeeded
request.always(function () {
});
}
return valid;
}
var dialog = $( "#dialog-form" ).dialog({
autoOpen: false,
height: 400,
width: 350,
modal: true,
buttons: {
"Add Group": addGroup,
Cancel: function() {
dialog.dialog( "close" );
}
},
close: function() {
form[ 0 ].reset();
}
});
form = dialog.find( "form" ).on( "submit", function( event ) {
event.preventDefault();
addGroup();
});
$( ".create-user" ).button().on( "click", function() {
dialog.dialog({
show: 'blind',
hide: 'blind'
});
dialog.dialog("open");
});
});
insert-group.php脚本:
<?php
$SKU_Group = $_POST['SKU Group'];
$host="xxxxxxxxxxx";
$dbName="xxxxxxx";
$dbUser="xxxx";
$dbPass="xxxxxxxxxxxxxx";
$pdo = new PDO("sqlsrv:server=".$host.";Database=".$dbName, $dbUser, $dbPass);
$sql = "INSERT INTO SKU_Group_Dim ([SKU Group]) VALUES (?)";
$stmt = $pdo->prepare($sql);
$result = $stmt->execute(array($SKU_Group));
echo json_encode($result);
?>
答案 0 :(得分:1)
修改声明
sku_group = $( "#group" )
与
sku_group = $( "#group" ).val();
这应该可以解决您的问题。
编辑以将TxtValue保存到数据库中...
$(function () {
var TxtValue = $("#group").val();
$("#submit").click(function (e) {
e.preventDefault();
if(!TxtValue){
$.ajax({
type: "POST",
url: "insert-group.php",
data: {[agrumentName]: TxtValue},
success: function(e){
console.log(e);
console.log("Row Insrerted");
}
});
}
else{
console.log("Cannot Insert Null Value");
}
})
})
用服务器函数参数替换[agrumentName]。
希望这会有所帮助:)