Question

我有以下xml文件：

<?xml version="1.0" encoding="UTF-8"?>
<group>    
    <List>
    <id_num>1</id_num>
    <car>cars</car>
        <value>          
            <color>green</color>
        <name>nissan</name>
        </value>
        <value>          
            <color>yellow</color>
        <name>renault</name>
        </value>
        <value>
             <color>black</color>
             <name>ford</name>
        </value>
    <value_number>3</value_number>
    </List>

    <List>
    <id_num>2</id_num>
    <car>cars</car>
         <value>          
            <color>blu</color>
        <name>porsche</name>
        </value>
        <value>          
            <color>white</color>
        <name>volvo</name>
        </value>        
    <value_number>2</value_number>
    </List>        
 </group>

使用xslt我想在节点中获得子节点的不同内容（颜色和名称）＆＃34; value＆＃34;即使它具有相同的名称已复制

所需的输出将是此xml文件：

<?xml version="1.0" encoding="UTF-8"?>
<group>group1</group>
<List>
<cars_1>
   <car>
       <color_info>green</color_info>
       <brand_name>nissan</brand_name>
   </car>
 <car>
       <color_info>yellow</color_info>
       <brand_name>renault</brand_name>
 </car>
  <car>
       <color_info>black</color_info>
        <brand_name>ford</brand_name>
  </car>
</cars_1>

<cars_2>
    <car>
       <color_info>blu</color_info>
       <brand_name>porsche</brand_name>
    </car>
    <car>
      <color_info>white</color_info>
     <brand_name>volvo</brand_name>
    </car>
</cars_2>
</List>

当我尝试使用时我无法区分具有不同内容的不同节点，因此他们的内容被复制

这是我得到的输出

<?xml version="1.0" encoding="utf-8"?>
<group>group1</group><List>
  <cars_1>
    <car>
      <color_info>green</color_info>
      <brand_name>nissan</brand_name>
    </car>
    <car>
      <color_info>yellow</color_info>
      <brand_name>renault</brand_name>
    </car>
    <car>
      <color_info>black</color_info>
      <brand_name>ford</brand_name>
    </car>
  </cars_1>
  <cars_2>
    <car>
      <color_info>blu</color_info>
      <brand_name>porsche</brand_name>
    </car>
    <car>
      <color_info>white</color_info>
      <brand_name>volvo</brand_name>
    </car>
  </cars_2>
</List><group>group1</group><List>
  <cars_1>
    <car>
      <color_info>blu</color_info>
      <brand_name>porsche</brand_name>
    </car>
    <car>
      <color_info>yellow</color_info>
      <brand_name>renault</brand_name>
    </car>
    <car>
      <color_info>black</color_info>
      <brand_name>ford</brand_name>
    </car>
  </cars_1>
  <cars_2>
    <car>
      <color_info>blu</color_info>
      <brand_name>porsche</brand_name>
    </car>
    <car>
      <color_info>white</color_info>
      <brand_name>volvo</brand_name>
    </car>
  </cars_2>
</List>

使用我的xsl文件获取：

<?xml version="1.0" encoding="UTF-8"?>        
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xlink="http://www.w3.org/1999/xlink">
        <xsl:output method="xml" indent="yes" encoding="utf-8" />  


<xsl:template match="/" >
<xsl:for-each select="group/List">

<group>group1</group>
<List>
<cars_1>
   <car>
       <color_info><xsl:value-of select="value/color"/>

    </color_info>
       <brand_name><xsl:value-of select="value/name"/></brand_name>
   </car>
 <car>
       <color_info>yellow</color_info>
       <brand_name>renault</brand_name>
 </car>
  <car>
       <color_info>black</color_info>
        <brand_name>ford</brand_name>
  </car>
</cars_1>

<cars_2>
    <car>
       <color_info>blu</color_info>
       <brand_name>porsche</brand_name>
    </car>
    <car>
      <color_info>white</color_info>
     <brand_name>volvo</brand_name>
    </car>
</cars_2>
</List>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

提前致谢

Answer 1

好吧，如果你这样做：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/group" >
    <group>
        <xsl:for-each select="List">
            <cars id="{id_num}">
                <xsl:for-each select="value">
                    <car>
                        <color_info>
                            <xsl:value-of select="color"/>
                        </color_info>
                        <brand_name>
                            <xsl:value-of select="name"/>
                        </brand_name>
                    </car>
                </xsl:for-each>
            </cars>
        </xsl:for-each>
    </group>
</xsl:template>

</xsl:stylesheet>

你会得到：

<?xml version="1.0" encoding="UTF-8"?>
<group>
  <cars id="1">
    <car>
      <color_info>green</color_info>
      <brand_name>nissan</brand_name>
    </car>
    <car>
      <color_info>yellow</color_info>
      <brand_name>renault</brand_name>
    </car>
    <car>
      <color_info>black</color_info>
      <brand_name>ford</brand_name>
    </car>
  </cars>
  <cars id="2">
    <car>
      <color_info>blu</color_info>
      <brand_name>porsche</brand_name>
    </car>
    <car>
      <color_info>white</color_info>
      <brand_name>volvo</brand_name>
    </car>
  </cars>
</group>

我相信它与预期结果足够接近。

xslt获取具有相同节点名称的不同子节点的内容

1 个答案: