我一直坚持这个问题一段时间了。我正在制作一个有三个几乎相同的片段的应用程序。我使用了this教程。我还尝试将数据从MainActivity传递到所有片段(片段为restaurantFragment,favouriteRestaurants,blockedRestaurants),只有 第三个片段存在问题。此外,当我更改哪些数据发送到哪个选项卡时 - 第一个和第二个选项卡获得正确的选项卡。第三个选项卡通常根本不被调用,如果它被调用它主要得到错误的数据,不像其他2个选项卡,并且当我选择第三个选项卡时也没有显示错误,并且很多次我尝试在调试时评估选项卡的数量通常只有2个选项卡 。我尝试了this,this和其他一些解决方案,但这些解决方案都不适用于我。
有时如果我在第二个标签之前选择第三个标签会显示正确的列表,但如果我先选择第二个标签,则只是复制它,而不是显示正确的值。
MainActivity:
TabLayout tabLayout = (TabLayout) findViewById(R.id.sliding_tabs);
tabLayout.addTab(tabLayout.newTab().setText(getString(R.string.tab_one)));
tabLayout.addTab(tabLayout.newTab().setText(getString(R.string.tab_two)));
tabLayout.addTab(tabLayout.newTab().setText(getString(R.string.tab_three)));
tabLayout.setTabGravity(TabLayout.GRAVITY_FILL);
tabLayout.setTabMode(TabLayout.MODE_FIXED);
final ViewPager viewPager = (ViewPager) findViewById(R.id.viewpager);
final PagerAdapter adapter = new PagerAdapter
(getSupportFragmentManager(), tabLayout.getTabCount());
viewPager.setAdapter(adapter);
viewPager.addOnPageChangeListener(new TabLayout.TabLayoutOnPageChangeListener(tabLayout));
tabLayout.setOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
viewPager.setCurrentItem(tab.getPosition());
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});
PagerAdapter:
public class PagerAdapter extends FragmentStatePagerAdapter {
int mNumOfTabs;
public PagerAdapter(FragmentManager fm, int NumOfTabs) {
super(fm);
this.mNumOfTabs = NumOfTabs;
}
@Override
public Fragment getItem(int position) {
switch (position) {
case 0:
return MapsFragment.newInstance(restaurants);
case 1:
return RestaurantsFragment.newInstance(restaurants);
case 2:
return MyRestaurantsFragment.newInstance(restaurants);
default:
return null;
}
}
@Override
public int getCount() {
return mNumOfTabs;
}
}
每个片段看起来都相同,如下所示:
public static MyRestaurantsFragment newInstance(ArrayList<Restaurant> restaurants) {
Bundle args = new Bundle();
args.putSerializable("restaurants",restaurants);
MyRestaurantsFragment fragment = new MyRestaurantsFragment();
fragment.setArguments(args);
return fragment;
}
@Override
public void onCreate(@Nullable Bundle savedInstanceState) {
restaurantList = (ArrayList<Restaurant>)getArguments().getSerializable("restaurants");
super.onCreate(savedInstanceState);
}
@Override
public View onCreateView(LayoutInflater inflater,
ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_my_restaurants, container, false);
listView = (ListView) view.findViewById(R.id.restaurants_list);
adapter = new RestaurantsListAdapter(getActivity(), restaurantList);
listView.setAdapter(adapter);
return view;
}
content_main:
<android.support.design.widget.AppBarLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:theme="@style/AppTheme.AppBarOverlay">
<android.support.v7.widget.Toolbar
android:id="@+id/toolbar"
android:layout_width="match_parent"
android:layout_height="?attr/actionBarSize"
android:background="?attr/colorPrimary"
app:popupTheme="@style/AppTheme.PopupOverlay" />
<android.support.design.widget.TabLayout
android:id="@+id/sliding_tabs"
android:layout_width="match_parent"
android:layout_height="wrap_content"
app:tabMode="scrollable" />
<android.support.v4.view.ViewPager
android:id="@+id/viewpager"
android:layout_width="match_parent"
android:layout_height="0px"
android:layout_weight="1"
android:background="@android:color/white" />
</android.support.design.widget.AppBarLayout>
答案 0 :(得分:1)
您应该将数据传递给适配器并调用
MyRestaurantsFragment tab3 = MyRestaurantsFragment.newInstance(restaurants);
而不是
MyRestaurantsFragment tab3 = new MyRestaurantsFragment();
答案 1 :(得分:1)
您是否在呼叫setUpWithViewPager(...)
?
// Give the TabLayout the ViewPager
TabLayout tabLayout = (TabLayout) root.findViewById(R.id.sliding_tabs);
tabLayout.setupWithViewPager(viewPager);
<强>更新强>
要查看标题,请尝试覆盖getPageTitle()
内的PagerAdapter
,如下所示:
@Override
public CharSequence getPageTitle(int position) {
if ( position == 0 ) {
return "Title 1";
} else if ( position == 1 ) {
return "Title 2";
} else {
return "Title 3";
}
}
此外,如果您使用tabLayout.setupWithViewPager
,则可以删除代码的这些部分:
tabLayout.addTab(tabLayout.newTab().setText(getString(R.string.tab_one)));
tabLayout.addTab(tabLayout.newTab().setText(getString(R.string.tab_two)));
tabLayout.addTab(tabLayout.newTab().setText(getString(R.string.tab_three)));
和
viewPager.addOnPageChangeListener(new TabLayout.TabLayoutOnPageChangeListener(tabLayout));
tabLayout.setOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
viewPager.setCurrentItem(tab.getPosition());
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});
我在这里假设您的布局是这样的:
<android.support.v4.view.ViewPager
android:layout_width="match_parent"
android:layout_height="match_parent">
<android.support.design.widget.TabLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_gravity="top" />
</android.support.v4.view.ViewPager>
更新2
尝试以这种方式更改getItem
方法:
@Override
public Fragment getItem(int position) {
if ( position == 0 ) {
return MapsFragment.newInstance(restaurants);
} else if ( position == 1 ) {
return RestaurantsFragment.newInstance(restaurants);
}
return MyRestaurantsFragment.newInstance(restaurants);
}