我正在进行Ch3编程练习,在Appel"现代编译器实现ML"中生成Tiger Parser。书。我的tiger.grm文件是here。我试图诊断的错误是由一元和二元减运算符的规则引起的减少 - 减少冲突。这是yacc错误:
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on OR
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on AND
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on GE
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on GT
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on LE
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on LT
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on NEQ
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on EQ
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on DIVIDE
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on TIMES
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on MINUS
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on PLUS
error: state 128: reduce/reduce conflict between rule 48 and rule 46 on RPAREN
state 128:
boolean : exp . AND exp
boolean : exp . OR exp
arithmetic : MINUS exp . (reduce by rule 46)
arithmetic : exp . PLUS exp
arithmetic : exp . MINUS exp
arithmetic : exp MINUS exp . (reduce by rule 48)
arithmetic : exp . DIVIDE exp
arithmetic : exp . TIMES exp
comparison : exp . EQ exp
comparison : exp . NEQ exp
comparison : exp . GT exp
comparison : exp . LT exp
comparison : exp . LE exp
comparison : exp . GE exp
我已将UNARY定义为优先于MINUS,并使用%prec
在我的规则中明确设置。当然,当我删除任一规则时,冲突消失,但语法将错误地解析MINUS标志。
我无法诊断此错误 - 有任何想法吗?
答案 0 :(得分:3)
狂野猜测:您的某个规则是否允许exp
为空?如果是这样,则会在exp
可选的任何地方产生歧义 - 例如在- exp
之前。
答案 1 :(得分:2)
作为接受答案的后续(他/她是对的) - 序列的制作中存在错误,允许exp
转到epsilon
。
以下是令人讨厌的代码(见最后一行):
sequence : LPAREN exp_sequence RPAREN ()
exp_sequence : (*epsilon*) ()
| exp seq ()
seq : (*epsilon*) () (*an exp sequence can be empty*)
| SEMICOLON exp exp_sequence () (*exps separated by semicolon*)
以下是更正后的代码:
sequence : LPAREN exp_sequence RPAREN ()
exp_sequence : (*epsilon*) ()
| exp seq ()
seq : (*epsilon*) () (*an exp sequence can be empty*)
| SEMICOLON exp seq () (*exps separated by semicolon*)