Question

我的测试数据库中有6个项目。搜索框位于http://vince.netau.net在搜索框中搜索任何内容之前，数据库中的所有6个项目都会显示出来。我需要在代码中更改哪些内容才能显示搜索框而没有任何结果？感谢

<?php
define("ROW_PER_PAGE",2);
require_once('db.php');
?>
<html>
<head>
<style>
body{width:615px;font-family:arial;letter-spacing:1px;line-height:20px;}
.tbl-qa{width: 100%;font-size:0.9em;background-color: #f5f5f5;}
.tbl-qa th.table-header {padding: 5px;text-align: left;padding:10px;}
.tbl-qa .table-row td {padding:10px;background-color: #FDFDFD;vertical-align:top;}
.button_link {color:#FFF;text-decoration:none; background-color:#428a8e;padding:10px;}
#keyword{border: #CCC 1px solid; border-radius: 4px; padding: 7px;background:url("demo-search-icon.png") no-repeat center right 7px;}
.btn-page{margin-right:10px;padding:5px 10px; border: #CCC 1px solid; background:#FFF; border-radius:4px;cursor:pointer;}
.btn-page:hover{background:#F0F0F0;}
.btn-page.current{background:#F0F0F0;}
</style>
</head>
<body>
<?php   
    $search_keyword = '';
    if(!empty($_POST['search']['keyword'])) {
        $search_keyword = $_POST['search']['keyword'];
    }
    $sql = 'SELECT * FROM posts WHERE post_title LIKE :keyword OR description LIKE :keyword OR post_at LIKE :keyword ORDER BY id DESC ';

    /* Pagination Code starts */
    $per_page_html = '';
    $page = 1;
    $start=0;
    if(!empty($_POST["page"])) {
        $page = $_POST["page"];
        $start=($page-1) * ROW_PER_PAGE;
    }
    $limit=" limit " . $start . "," . ROW_PER_PAGE;
    $pagination_statement = $pdo_conn->prepare($sql);
    $pagination_statement->bindValue(':keyword', '%' . $search_keyword . '%', PDO::PARAM_STR);
    $pagination_statement->execute();

    $row_count = $pagination_statement->rowCount();
    if(!empty($row_count)){
        $per_page_html .= "<div style='text-align:center;margin:20px 0px;'>";
        $page_count=ceil($row_count/ROW_PER_PAGE);
        if($page_count>1) {
            for($i=1;$i<=$page_count;$i++){
                if($i==$page){
                    $per_page_html .= '<input type="submit" name="page" value="' . $i . '" class="btn-page current" />';
                } else {
                    $per_page_html .= '<input type="submit" name="page" value="' . $i . '" class="btn-page" />';
                }
            }
        }
        $per_page_html .= "</div>";
    }

    $query = $sql.$limit;
    $pdo_statement = $pdo_conn->prepare($query);
    $pdo_statement->bindValue(':keyword', '%' . $search_keyword . '%', PDO::PARAM_STR);
    $pdo_statement->execute();
    $result = $pdo_statement->fetchAll();
?>
<form name='frmSearch' action='' method='post'>
<div style='text-align:right;margin:20px 0px;'><input type='text' name='search[keyword]' value="<?php echo $search_keyword; ?>" id='keyword' maxlength='25'></div>
<table class='tbl-qa'>
  <thead>
    <tr>
      <th class='table-header' width='20%'>Title</th>
      <th class='table-header' width='40%'>Description</th>
      <th class='table-header' width='20%'>Date</th>
    </tr>
  </thead>
  <tbody id='table-body'>
    <?php
    if(!empty($result)) { 
        foreach($result as $row) {
    ?>
      <tr class='table-row'>
        <td><?php echo $row['post_title']; ?></td>
        <td><a href="<?php echo $row['description']; ?>"
                <td><?php echo $row['description']; ?></td>
                <td><?php echo $row['post_at']; ?></td>
      </tr>
    <?php
        }
    }
    ?>
  </tbody>
</table>
<?php echo $per_page_html; ?>
</form>
</body>
</html>

Answer 1

您必须将所有数据库php代码移动到第一个if语句中。您正在检查表单是否已提交但是仍然运行查询。通过将所有代码移动到if语句中，除非实际提交表单，否则将阻止查询运行。您已经在检查结果是否为空，因此结果未定义是可以的。

$search_keyword = '';
    if(!empty($_POST['search']['keyword'])) {
        $search_keyword = $_POST['search']['keyword'];
$sql = 'SELECT * FROM posts WHERE post_title LIKE :keyword OR description LIKE :keyword OR post_at LIKE :keyword ORDER BY id DESC ';

    /* Pagination Code starts */
    $per_page_html = '';
    $page = 1;
    $start=0;
    if(!empty($_POST["page"])) {
        $page = $_POST["page"];
        $start=($page-1) * ROW_PER_PAGE;
    }
    $limit=" limit " . $start . "," . ROW_PER_PAGE;
    $pagination_statement = $pdo_conn->prepare($sql);
    $pagination_statement->bindValue(':keyword', '%' . $search_keyword . '%', PDO::PARAM_STR);
    $pagination_statement->execute();

    $row_count = $pagination_statement->rowCount();
    if(!empty($row_count)){
        $per_page_html .= "<div style='text-align:center;margin:20px 0px;'>";
        $page_count=ceil($row_count/ROW_PER_PAGE);
        if($page_count>1) {
            for($i=1;$i<=$page_count;$i++){
                if($i==$page){
                    $per_page_html .= '<input type="submit" name="page" value="' . $i . '" class="btn-page current" />';
                } else {
                    $per_page_html .= '<input type="submit" name="page" value="' . $i . '" class="btn-page" />';
                }
            }
        }
        $per_page_html .= "</div>";
    }

    $query = $sql.$limit;
    $pdo_statement = $pdo_conn->prepare($query);
    $pdo_statement->bindValue(':keyword', '%' . $search_keyword . '%', PDO::PARAM_STR);
    $pdo_statement->execute();
    $result = $pdo_statement->fetchAll();
    }

Answer 2

简化Chip的答案..你只需要让你的第一个IF控制你所有的搜索和显示代码......

   $search_keyword = $_POST['search']['keyword'];
   }  <<  remove this closing curly bracket

  and put it here
    .......
    $result = $pdo_statement->fetchAll();
 }  // END if $_POST['search']['keyword']  is !empty
 ?>

搜索PHP - 如何调出没有结果的搜索框

2 个答案: