我是firebase的新手,为我创建了一个Firebase结构,基本上我要做的就是列出FirebaseDB的所有用户。
我想在swift中创建一个对应的类到下面的firebase数据结构。
"users" : {
"A654tdC5uBPoKQzJnpZIpwOfsaJ3" : {
"groups" : {
"-KZ7fl3I4W7YWuGk6l9k" : true,
"-KclzmvvJF54cAg14P92" : true,
"-KclzpzrJOhCOWL5_jvw" : true,
"-Kcm33N1B_oiVYrQWh3n" : true,
"-Kcm3GfRaaGfztEBmflp" : true
},
"location" : {
"coordinates" : [ 6.59086, 3.3914267 ],
"name" : "Oyebanjo Solarin Street, Lagos",
"visibility" : true
},
"photoUrl" : "http://pbs.twimg.com/profile_images/511567946351923201/YBqqKc78_normal.jpeg",
"username" : "Kamiye",
"visibilityToSelectContacts" : {
"contacts" : {
"gFTCpzgSJDOsrVKWbAJp0Z1JFXp1" : true,
"rRxT6x87kgSjTwZfa7M8ZwzdFkC3" : true
},
"visibility" : true
}
},
这是我尝试过的,而且不起作用
class LContact {
var visibliityToSelectedContacts: VisibilityToSelectContacts?
var photoUrl: String?
let username: String
var location: LALocation?
var groudId = [String]()
init (value: [String: Any] ) {
self.username = value["username"] as! String
self.photoUrl = value["photoUrl"] as? String
self.location = LALocation(value: value["coordinates"] as? [String:Any] ?? [:])
self.groudId = (value["groups"] as? [String])!
}
}
class VisibilityToSelectContacts {
var contacts = [String]()
var visibility: Bool
init(value: [String: Any]) {
self.contacts = [value["contacts"] as! String]
self.visibility = value["visibility"] as! Bool
}
}
struct LALocation {
var long: Double
var lat: Double
var address: String!
var visibility: Bool!
init(long: Double, lat: Double, address: String?, visibility: Bool) {
self.long = long
self.lat = lat
self.address = address
self.visibility = visibility
}
init?(value: [String: Any]) {
guard let long = value["0"] as? Double,
let lat = value["1"] as? Double else {return nil}
self.long = long
self.lat = lat
self.address = value["name"] as? String
self.visibility = value["visibility"] as? Bool
}
}
答案 0 :(得分:4)
让我告诉你一些可能有用的代码。它不是整个班级,但所有的概念都在那里。我也使用简化的Firebase结构,但同样,概念是相同的:
这是Firebase结构
users
a_uid
email: "some email"
groups
group_1: true
group_2: true
location
coords: "[52.5, 67.1]"
name: "Oyebanjo Solarin Street, Lagos"
visibility: true
username: "some username"
首先,似乎每个用户的位置都适合作为一个结构。
struct LocationStruct {
var coords: String?
var name: String?
var visibility: Bool?
}
然后我们在用户类中使用该结构。在这个例子中,我们传递一个用户的快照来初始化类并解构它以填充类变量。
class UserClass {
var email = ""
var username = ""
var groupsDict: [String: Any]
var loc = LocationStruct()
init(snap: FIRDataSnapshot) {
let userDict = snap.value as! [String: Any]
self.email = userDict["email"] as! String
self.username = userDict["username"] as! String
self.groupsDict = userDict["groups"] as! [String: Any]
let locationDict = userDict["location"] as! [String: Any]
self.loc.coords = locationDict["coords"] as? String
self.loc.name = locationDict["name"] as? String
self.loc.visibility = locationDict["visibility"] as? Bool
}
}
这是在单个用户中读取并填充UserClass
的代码 ref.child("users").child("a_uid")
.observeSingleEvent(of: .value, with: { snapshot in
let user = UserClass(snap: snapshot)
//this code is just to show the UserClass was populated.
print(user.email)
print(user.username)
for group in user.groupsDict { //iterate over groups
print(group) //and print each one
}
print(user.loc.coords!) //print the location data
print(user.loc.name!)
print(user.loc.visibility!)
})
您的结构中唯一剩下的问题,是一个visibilityToSelectContacts节点,它有一个子节点联系人。
基本上,UserClass中userDict的高级字典将有一个名为visibilityToSelectContacts的子项,然后它有一个子联系人,它有一个key的子词典:> gFTCpzgSJDOsrVKWbAJp0Z1JFXp1" :是的。喜欢这个
userDict
visibilityToSelectContacts
contacts
contant_0: true
contant_1: true
我会让你把这个结构搞定(提示:它的设计模式相同)
答案 1 :(得分:0)
尝试使用3d派对库进行取消装箱,例如this 还要检查用于提取未来孩子的密钥,例如:
LALocation(value: value["coordinates"] as? [String:Any] ?? [:])
这里你需要:
LALocation(value: value["location"] as? [String:Any] ?? [:])
并且在获取数据后不要忘记提取对象标识snapshot.key