Question

这是我到目前为止所做的，但我被困住了。我能够过滤我想要的值，但我无法弄清楚如何获取这些过滤的值，而不是在列表返回列标题中获取它们。

这就是我的数据：

Taxa,Pop_1,Pop_2,Pop_3,Pop_4,Pop_5,Pop_6,Pop_7
IPs216:C95NTANXX:1:250590968,0.000023,0.999865,0.000023,0.000023,0.000023,0.000023,0.000022
IPs159:C95NTANXX:1:250591032,0.000023,0.000023,0.000023,0.000023,0.000023,0.999864,0.000023
IPs286:C95NTANXX:1:250591013,0.000024,0.000024,0.000024,0.000024,0.000024,0.000024,0.999856
IPs63:C95NTANXX:1:250591090,0.000024,0.000024,0.409426,0.352769,0.000024,0.237707,0.000024
IPs892:C95NTANXX:1:250591054,0.000024,0.000024,0.999853,0.000024,0.000024,0.000024,0.000024
IPs264:C95NTANXX:1:250590956,0.000023,0.000023,0.000023,0.999864,0.000023,0.000023,0.000023
IPs716:C95NTANXX:1:250590960,0.000023,0.000023,0.999864,0.000023,0.000023,0.000023,0.000023
IPs854:C95NTANXX:1:250590951,0.000022,0.080564,0.919325,0.000022,0.000022,0.000022,0.000022
IPs914:C95NTANXX:1:250591052,0.238472,0.000023,0.000023,0.686966,0.000023,0.074471,0.000023
IPs729:C95NTANXX:1:250591019,0.000022,0.000022,0.000022,0.999869,0.000022,0.000022,0.000022

这是我的代码：

f=open("/home/mjohnson/Desktop/Millet_Files/final_analysis/trees/pop_info/kodo_mod_7.meanQ" , "r")
col_titles=list()
pop_values=list()
f.readline()
filtered=list()
#gives a list with column names, i need to index this to pair values with them
a=open("/home/mjohnson/Desktop/Millet_Files/final_analysis/trees/pop_info/kodo_mod_7.meanQ" , "r")
col_titles.append(a.readline())
col_names=list()
for names in col_titles:
    q=names.strip('\n').split(',')
    col_names.append(q)
#end of getting column names

for line in f:
    x=line.strip('\n').split(',')
    x=x[1:] #this has the list ignore the first values, so taxa names ignored 
    for score in x:
        if float(score) > 0.5:
            filtered.append(score+'\n')

Answer 1

您为什么要自己解析CSV文件？请参阅标准CSV模块。特别是你想要的是csv.DictReader()类。

例如：

    public static void ReadEventLog()
    {
        // Line in question below
        EventLog eventLog = new EventLog(EvlLocation);
        EventLogEntryCollection eventLogEntries = eventLog.Entries;
        int eventLogEntryCount = eventLogEntries.Count;
        for (int i = 0; i < eventLogEntries.Count; i++)
        {
            EventLogEntry entry = eventLog.Entries[i];
            //Do Some processing on the entry
        }
        _LogEntries = eventLogEntries.Cast<EventLogEntry>().ToList();
    }

Answer 2

2件事：

1）你不必扔掉第一列，你可以通过调整循环来跳过它

2）使用枚举对你已经存在的东西进行编号。

for i, score in enumerate(x[1:]):
    if float(score) > 0.5:
        filtered.append(col_names[i]+'\n')

按行过滤值，如果高于阈值则返回列标题

2 个答案: