Question

您好我从生物测量设备获取数据，如： -

|Id     |EmpCode    | WorkDate                   |InOutMode  
|247    |51         | 2017-02-13 20:08:52.000    |0          
|392    |51         | 2017-02-13 22:38:51.000    |1          
|405    |51         | 2017-02-13 22:59:18.000    |0          
|415    |51         | 2017-02-13 23:18:17.000    |1          
|423    |51         | 2017-02-13 23:33:44.000    |0          
|456    |51         | 2017-02-13 01:30:15.000    |1          
|463    |51         | 2017-02-13 02:52:02.000    |0          
|483    |51         | 2017-02-13 05:11:54.000    |1          
|1034   |51         | 2017-02-14 20:09:23.000    |0          
|1172   |51         | 2017-02-14 21:59:23.000    |1          
|1217   |51         | 2017-02-14 22:30:28.000    |0
|1214   |51         | 2017-02-14 22:30:39.000    |0          
|1238   |51         | 2017-02-14 22:49:51.000    |1          
|1257   |51         | 2017-02-14 23:19:10.000    |0          
|1315   |51         | 2017-02-14 05:04:16.000    |1          
|1323   |51         | 2017-02-14 05:05:17.000    |0          
|1329   |51         | 2017-02-14 05:08:17.000    |1
|1330   |51         | 2017-02-14 05:08:18.000    |1

我想从上面的表记录中获取数据，如： -

|EmpCode   |WorkDate       |CheckIn    |CheckOut   |TotalHours
|51        |2017-02-13     |20:08:52   |22:38:51   |2.499722000
|51        |2017-02-13     |22:59:18   |23:18:17   |0.316388000
|51        |2017-02-13     |23:33:44   |01:30:15   |3.103330000
|51        |2017-02-13     |02:52:02   |05:11:54   |2.331111000
|51        |2017-02-14     |20:09:23   |21:59:23   |1.833333000
|51        |2017-02-14     |22:30:28   |22:49:51   |0.323055000
|51        |2017-02-14     |23:19:10   |05:04:16   |5.323055000
|51        |2017-02-14     |05:05:17   |05:08:18   |0.050000000

PS：重复的IN或OUT被忽略原始数据中的第13,14,17和18行。 2.分钟数小时是小时计算中的小时数。

我需要有关Sql-Server查询的帮助才能获得这些结果。

我当前的代码对我没有帮助，也留下一些行并得到错误的结果和总共几个小时谢谢：）

注意： - 当我的查询执行时缺少两行： -

|456    |51         | 2017-02-13 01:30:15.000    |1          
|463    |51         | 2017-02-13 02:52:02.000    |0

Answer 1

假设In中的0和1已出局。

我添加了Overnight列，以便在第二天1时返回CheckOut。如果您不需要，可以将其评论出来。

使用cross apply()

rextester：http://rextester.com/ENFRC28977

with cte as (
  select 
      Id
    , EmpCode
    , WorkDate
    , InOutMode
    , Lag_InOutMode = Lag(InOutMode) over (order by EmpCode, WorkDate)
  from t
)
select 
    i.EmpCode
  , WorkDate = convert(varchar(10),convert(date,i.WorkDate))
  , Overnight = case when datediff(day,i.WorkDate,o.WorkDate)>0 then 1 else 0 end
  , CheckIn  = convert(time,i.WorkDate)
  , CheckOut = convert(time,o.WorkDate)
  , TotalHours = datediff(second,i.WorkDate,o.WorkDate)/3600.0
from cte i 
cross apply (
    select top 1 WorkDate
    from cte o
    where o.EmpCode = i.EmpCode
      and o.InOutMode = 1
      and o.Lag_InOutMode != 1
      and o.WorkDate > i.WorkDate
    order by o.WorkDate asc
    ) as o
where i.InOutMode = 0 
  and i.Lag_InOutMode != 0
order by i.WorkDate

返回：

+---------+------------+-----------+----------+----------+------------+
| EmpCode |  WorkDate  | Overnight | CheckIn  | CheckOut | TotalHours |
+---------+------------+-----------+----------+----------+------------+
|      51 | 2017-02-13 |         0 | 02:52:02 | 05:11:54 | 2,331111   |
|      51 | 2017-02-13 |         0 | 20:08:52 | 22:38:51 | 2,499722   |
|      51 | 2017-02-13 |         0 | 22:59:18 | 23:18:17 | 0,316388   |
|      51 | 2017-02-13 |         1 | 23:33:44 | 05:04:16 | 5,508888   |
|      51 | 2017-02-14 |         0 | 05:05:17 | 05:08:17 | 0,050000   |
|      51 | 2017-02-14 |         0 | 20:09:23 | 21:59:23 | 1,833333   |
|      51 | 2017-02-14 |         0 | 22:30:28 | 22:49:51 | 0,323055   |
+---------+------------+-----------+----------+----------+------------+

我在0之前没有看到InOutMode '2017-02-13 01:30:15'，因此我的结果不包含以下行：

|51        |2017-02-13     |23:33:44   |01:30:15   |3.103330000

Bio-Metric设备记录

1 个答案: