Question

我正在尝试为此架构编写有效的XML：

<xsd:complexType name="resourceType">
    <annotation xmlns="http://www.w3.org/2001/XMLSchema">
        <documentation>
            A resource root within a deployment.
        </documentation>
    </annotation>
    <xsd:all>
        <xsd:element name="filter" type="filterType" minOccurs="0">
            <annotation xmlns="http://www.w3.org/2001/XMLSchema">
                <documentation>
                    A path filter specification for this resource root (optional). By default all paths are accepted.
                </documentation>
            </annotation>
        </xsd:element>
    </xsd:all>
    <xsd:attribute name="name" type="xsd:string" use="optional">
        <annotation xmlns="http://www.w3.org/2001/XMLSchema">
            <documentation>
                The name of this resource root (optional). If not specified, defaults to the value of the path
                attribute.
            </documentation>
        </annotation>
    </xsd:attribute>
    <xsd:attribute name="path" type="xsd:string" use="required">
        <annotation xmlns="http://www.w3.org/2001/XMLSchema">
            <documentation>
                The path of this resource root, relative to the path in which the module.xml file is found.
            </documentation>
        </annotation>
    </xsd:attribute>
</xsd:complexType>

我是XML和XSD的新手，我将不胜感激：根据这个XSD，什么是一个有效的示例XML文档？

Answer 1

有两个问题阻止任何XML对提供的XSD有效：

XSD包含对未定义类型的引用filterType。
XSD指定没有根元素。

将filterType替换为xsd:string并添加根元素，r类型等于XSD中的顶级complexType，然后修改XSD，

<?xml version="1.0" encoding="UTF-8"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <xsd:element name="r" type="resourceType"/>
  <xsd:complexType name="resourceType">
    <annotation xmlns="http://www.w3.org/2001/XMLSchema">
      <documentation>
        A resource root within a deployment.
      </documentation>
    </annotation>
    <xsd:all>
      <xsd:element name="filter" type="xsd:string" minOccurs="0">
        <annotation xmlns="http://www.w3.org/2001/XMLSchema">
          <documentation>
            A path filter specification for this resource root
            (optional). By default all paths are accepted.
          </documentation>
        </annotation>
      </xsd:element>
    </xsd:all>
    <xsd:attribute name="name" type="xsd:string" use="optional">
      <annotation xmlns="http://www.w3.org/2001/XMLSchema">
        <documentation>
          The name of this resource root (optional). If not specified,
          defaults to the value of the path attribute.
        </documentation>
      </annotation>
    </xsd:attribute>
    <xsd:attribute name="path" type="xsd:string" use="required">
      <annotation xmlns="http://www.w3.org/2001/XMLSchema">
        <documentation>
          The path of this resource root, relative to the path in
          which the module.xml file is found.
        </documentation>
      </annotation>
    </xsd:attribute>
  </xsd:complexType>
</xsd:schema>

将成功验证以下XML，例如：

<?xml version="1.0" encoding="UTF-8"?>
<r path="">
  <filter/>
</r>

向我展示这个XSD的示例XML？

1 个答案: