Question

我在数据库中有一个标签分隔列，其中包含标题字段及其相关结果。我需要一个查询的帮助，该查询将根据IP列在单独的行中返回该数据。以下是数据样本以及所需结果。

以下查询会产生此结果。

Sub foo()
   Dim X() as Long
   Redim X(1 to 3) as long ' <-- Will now refer to the local variable X
   ....
End Sub

这是理想的结果。

DECLARE @Tmp TABLE (ID int Identity(1,1), IP nvarchar(255),Results NVARCHAR(max));
INSERT into @Tmp select top 1 ip, Results from MyTable where results like 'Package%'
select * from @Tmp

这是从SQL结果窗口复制到剪贴板的数据。

IP              Package      Installed Version          Required Version
10.48.8.28      nss          3.21.0-9.el7_2.x86_64      3.21.3-2.el7_3
10.48.8.28      nss-sysinit  3.21.0-9.el7_2.x86_64      3.21.3-2.el7_3
10.48.8.28      nss-tools    3.21.0-9.el7_2.x86_64      3.21.3-2.el7_3
10.48.8.28      nss-util     3.21.0-2.2.el7_2.x86_64    3.21.3-1.1.el7_3

Answer 1

如果您使用的是SQL Server 2016，则可以使用STRING_SPLIT()

根据Aaron Bertrand的说法，这是最快的方式。见https://sqlperformance.com/2016/03/sql-server-2016/string-split

Declare @YourTable table (ID int,IP varchar(50),TabString varchar(max));
Insert Into @YourTable values
(1,'444.333.222.11','Package    Installed Version   Required Version
nss 3.21.0-9.el7_2.x86_64   3.21.3-2.el7_3
nss-sysinit 3.21.0-9.el7_2.x86_64   3.21.3-2.el7_3
nss-tools   3.21.0-9.el7_2.x86_64   3.21.3-2.el7_3
nss-util    3.21.0-2.2.el7_2.x86_64 3.21.3-1.1.el7_3');


;WITH CTE_Lines AS
(
select ID, IP, a.ROWID , a.Lines from @YourTable
    CROSS APPLY (
        SELECT 
           ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS ROWID, value Lines
         FROM STRING_SPLIT(TabString, CHAR(13)) --Splits by new lines
    ) a
), CTE_Columns AS
(
SELECT ID, IP, ROWID, b.ColsID, b.[Cols] FROM CTE_Lines
    CROSS APPLY (
    SELECT 
        ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS ColsID,
        value [Cols] 
        FROM STRING_SPLIT(Lines, CHAR(9)) --Splits by tabs
    ) b 
    WHERE ROWID <> 1 --Removes the headers
)

SELECT ID, IP,  [1] Package, [2] [Installed Version],[3] [Required Version]  FROM 
(
    SELECT ID, IP, ROWID, ColsID, [Cols]  FROM CTE_Columns 
) a
PIVOT (MAX(a.Cols) FOR ColsId in ([1],[2],[3])) as pvt

Answer 2

创建示例数据

$('selector').effect()

看起来像这样

选项1（带解析功能）

Declare @YourTable table (ID int,IP varchar(50),TabString varchar(max))
Insert Into @YourTable values
(1,'444.333.222.11','Package Installed Version  Required Version
nss 3.21.0-9.el7_2.x86_64   3.21.3-2.el7_3
nss-sysinit 3.21.0-9.el7_2.x86_64   3.21.3-2.el7_3
nss-tools   3.21.0-9.el7_2.x86_64   3.21.3-2.el7_3
nss-util    3.21.0-2.2.el7_2.x86_64 3.21.3-1.1.el7_3')

<强>返回

选项2（没有解析功能）

Select A.ID
      ,A.IP
      ,Package             = Pos1
      ,[Installed Version] = Pos2
      ,[Required Version]  = Pos3
 From  @YourTable A
 Cross Apply [dbo].[udf-Str-Parse](A.TabString,char(13)) B
 Cross Apply [dbo].[udf-Str-Parse-Row](B.RetVal,char(9)) C
 Where B.RetVal is not null and B.RetSeq>1

<强>返回

感兴趣的解析功能

Select A.ID
      ,A.IP
      ,Package             = Pos1
      ,[Installed Version] = Pos2
      ,[Required Version]  = Pos3
 From  @YourTable A
 Cross Apply ( 
                Select RetSeq = Row_Number() over (Order By (Select null))
                      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                From  (Select x = Cast('<x>' + replace((Select replace(A.TabString,char(13),'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as X
                Cross Apply x.nodes('x') AS B(i)
             ) B
 Cross Apply (
                Select Pos1 = ltrim(rtrim(xDim.value('/x[1]','varchar(max)')))
                      ,Pos2 = ltrim(rtrim(xDim.value('/x[2]','varchar(max)')))
                      ,Pos3 = ltrim(rtrim(xDim.value('/x[3]','varchar(max)')))
                      ,Pos4 = ltrim(rtrim(xDim.value('/x[4]','varchar(max)')))
                From  (Select Cast('<x>' + replace((Select replace(B.RetVal,char(9),'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml) as xDim) as X 
             ) C
 Where B.RetVal is not null and B.RetSeq>1

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10))
Returns Table 
As
Return (  
    Select RetSeq = Row_Number() over (Order By (Select null))
          ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
    From  (Select x = Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A 
    Cross Apply x.nodes('x') AS B(i)
);
--Thanks Shnugo for making this XML safe
--Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ')
--Select * from [dbo].[udf-Str-Parse]('this,is,<test>,for,< & >',',')

SQL拆分制表符分隔列

2 个答案: