Question

我刚刚开始使用python，我正在尝试创建一个简单的Ricky计算器。

def ricky_adds(x,y):
    num1 = x
    num2 = y
    if num1 >= 10:
        num1 = input("No. I said A number, not multiple numbers dummy. Try again :")
    if num1 < 0:
        num1 = input("Wow you're dumb, I said a number, not some imaginary shit. Try again :")
    num2 = y
    if num2 >= 10:
        num2 = input("No. I said A number, not multiple numbers dummy. Try again :")
    if num2 < 0:
        num2 = input("Wow you're dumb, I said a number, not some imaginary shit. Try again :")

    result = num1 + num2
    return result

ricky_adds(input("Gimmie a number. :"), input("Smokes, let's go. Another number, c'mon. :"))

但是收到此错误

Gimmie a number. :Smokes, let's go. Another number, c'mon. :
Traceback (most recent call last): 
  File "..\Playground\", line 17, in <module> 
    ricky_adds(input("Gimmie a number. :"), input("Smokes, let's go. Another number, c'mon. :")) 
EOFError: EOF when reading a line

我无法弄清楚如何修复错误。我可以不使用“input（）”来获取参数的用户输入吗？

Answer 1

好的，谢谢大家的帮助到目前为止。这就是我现在所拥有的：

def main():
    x = int(input("Gimmie a number. :"))
    y = int(input("Smokes, let's go. Another number, c'mon. :"))

    print("Here's the answer. See, Julian? I out smarted your stupid books and did that arthritis in my head and got " + str(ricky_adds(x,y)))

def ricky_adds(x,y):
    num1 = x
    num2 = y
    lessthanzeroerror = "Wow you're dumb, I said a number, not some imaginary shit. Try again :"
    greaterthantenerror = "No. I said A number, not multiple numbers dummy. Try again :"
    if num1 >= 10:
        num1 = int(input(greaterthantenerror + ":"))
    elif num1 < 0:
        num1 = int(input(lessthanzeroerror + ":"))
    if num2 >= 10:
        num2 = int(input(greaterthantenerror + ":"))
    elif num2 < 0:
        num2 = int(input(lessthanzeroerror + ":"))

    result = num1 + num2
    return result

main()

上一个答案：所以我想出了如何使用Textwrangler。

我也改变了：

ricky_adds(input("Gimmie a number. :"), input("Smokes, let's go. Another number, c'mon. :"))

为：

print(ricky_adds(input("Gimmie a number. :"), input("Smokes, let's go. Another number, c'mon. :")))

它有效。谢谢大家的指导性问题。

Answer 2

你需要重新认识你的逻辑。数字可以是＆gt; = 10而不是多个数字。考虑使用nested if statements来实现您的目标。

def ricky_adds(x,y):
    num1 = x
    num2 = y

    if num1 >= 10:
        num1 = input("No. I said A number, not multiple numbers dummy. Try again :") # what happens after this statement? what is the purpse of this input. You need to nest the statements to continue in a logical manner.
    if num1 < 0:
        num1 = input("Wow you're dumb, I said a number, not some imaginary shit. Try again :")

    if num2 >= 10:
        num2 = input("No. I said A number, not multiple numbers dummy. Try again :")
    if num2 < 0:
        num2 = input("Wow you're dumb, I said a number, not some imaginary shit. Try again :")

以下是压缩代码的方法

if (num1>= 10 or num2 >= 10):
    print("you have enter a number greater then 10")
    data = input("try again")
    if......
elif (num1 < 0 or num2 < 0):
    print("you number is less than 0")

    return (num1 + num2)

此外，您需要整数输入，而不是您拥有的。创建一个主要功能，可以帮助您实现这一目标。

def main():
    x = int(input("Gimmie a number. :"))
    y = int(input("Smokes, let's go. Another number, c'mon. :"))

ricky_adds(x,y)

尝试使用用户输入作为参数的EOF错误

2 个答案: