Question

我有两个带有两个不同网址的ImageButton。当我点击图像时，它会返回一个白色的屏幕。我不知道是什么问题。欢迎任何编辑或建议。

谢谢！

主要活动

public class main extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main2);

        ImageButton amazon = (ImageButton)findViewById(R.id.imagebutton1);
        ImageButton flipkart = (ImageButton)findViewById(R.id.imagebutton2);

        amazon.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                Toast.makeText(getApplicationContext(),"Amazon",Toast.LENGTH_LONG).show();// display the toast on home button click
                Intent intent  = new Intent(main.this, MainActivity.class);
                intent.setData(Uri.parse("http://www.amazon.com"));
                WebView webview = new WebView(main.this);
                setContentView(webview);

                startActivity(intent);



            }
        });
        flipkart.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                Toast.makeText(getApplicationContext(),"Flipkart",Toast.LENGTH_LONG).show();// display the toast on you tube button click
                Intent intent  = new Intent(main.this, MainActivity.class);
                intent.setData(Uri.parse("http://www.flipkart.in"));
                startActivity(intent);
            }
        });

    }

我的网络视图活动

public class MainActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    WebView htmlWebView = (WebView) findViewById(R.id.webView);
    htmlWebView.setWebViewClient(new CustomWebViewClient());
    WebSettings webSetting = htmlWebView.getSettings();
    webSetting.setJavaScriptEnabled(true);
    webSetting.setDisplayZoomControls(true);
    htmlWebView.loadUrl("");
}



 class CustomWebViewClient extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        view.loadUrl(url);
        return true;
    }
}

Answer 1

是否要在应用中加载网址或想要通过外部浏览器打开。我已经给出了在webview中打开url的剪切代码，如下面的应用程序所示：

   WebView mynews;
        ProgressBar pb;
        @Override
        protected void onCreate(@Nullable Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.newsreadscreen);
            Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
            setSupportActionBar(toolbar);
            getSupportActionBar().setDisplayHomeAsUpEnabled(true);
        pb= (ProgressBar) findViewById(R.id.progress_bar);
            mynews= (WebView) findViewById(R.id.mynews);
            mynews.getSettings().setJavaScriptEnabled(true);
            mynews.getSettings().setDefaultFontSize(17);
            mynews.getSettings().setDisplayZoomControls(true);
            mynews.getSettings().setDomStorageEnabled(true);
            mynews.getSettings().setLoadsImagesAutomatically(true);



            mynews.setWebViewClient(new WebViewClient() {

                @Override
                public boolean shouldOverrideUrlLoading(WebView view, String url) {
                 pb.setVisibility(View.VISIBLE);
                    view.loadUrl(url);
                    return true;
                }

                @Override
                public void onPageFinished(WebView view, String url) {
                    pb.setVisibility(View.GONE);
                    super.onPageFinished(view, url);
                }

                @Override
                public void onPageStarted(WebView view, String url, Bitmap favicon) {
                  pb.setVisibility(View.VISIBLE);
                    super.onPageStarted(view, url, favicon);

                }
            });

   mynews.loadUrl("https://www.google.co.in");

这是我编辑的代码

 amazon.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                Toast.makeText(getApplicationContext(),"Amazon",Toast.LENGTH_LONG).show();// display the toast on home button click
                Intent intent  = new Intent(main.this, MainActivity.class);
               intent.putExtra("url","http://www.amazon.com");
                startActivity(intent);



            }
        });

获取MainActivity.Class onCreateMethod上的值，如下所示

String url=getIntent().getStringExtra("url");
mynews.loadUrl(url);

我的网页浏览空白

1 个答案: