我在将SQL查询转换为Doctrine时遇到了问题。
我有以下设置:
Id | template_type | object_id |名字|路径| rgt | lft |水平
Id |其他|列
Id |其他|列
我正在尝试选择模板类型为“Property”的路径(这些路径在属性表中总是有'object_id'的记录),我正在尝试加入父路径(它总是有一条记录在开发表中。)
以下原始SQL完美运行:
SELECT
node.*,
parent.*,
development.*,
property.*
FROM
path AS node,
path AS parent,
development,
property
WHERE
node.lft
BETWEEN
parent.lft AND parent.rgt
AND
node.template_type = 'Property'
AND
parent.level = node.level - 1
AND
development.id = parent.object_id
AND
property.id = node.object_id
当试图将其转换为Doctrine时,我似乎遇到了麻烦。
$q = Doctrine_Query::create()
->select("node.*")
->addSelect("parent.*")
->addSelect("development.*")
->addSelect("property.*")
->from("Path node")
->addFrom("Path parent")
->addFrom("Development development")
->addFrom("Property property")
->where("node.lft BETWEEN parent.lft AND parent.rgt")
->addWhere("node.template_type = 'Property'")
->addWhere("parent.level = node.level - 1")
->addWhere("development.id = parent.object_id")
->addWhere("property.id = node.object_id");
它生成的查询是:
SELECT p.id AS p__id,
p.template_type AS p__template_type,
p.object_id AS p__object_id,
p.created_at AS p__created_at,
p.updated_at AS p__updated_at,
p.meta_page_title AS p__meta_page_title,
p.meta_navigation_title AS p__meta_navigation_title,
p.meta_path AS p__meta_path,
p.meta_keywords AS p__meta_keywords,
p.meta_description AS p__meta_description,
p.meta_visible_in_navigation AS p__meta_visible_in_navigation,
p.root_id AS p__root_id,
p.lft AS p__lft,
p.rgt AS p__rgt,
p.level AS p__level,
p2.id AS p2__id,
p2.template_type AS p2__template_type,
p2.object_id AS p2__object_id,
p2.created_at AS p2__created_at,
p2.updated_at AS p2__updated_at,
p2.meta_page_title AS p2__meta_page_title,
p2.meta_navigation_title AS p2__meta_navigation_title,
p2.meta_path AS p2__meta_path,
p2.meta_keywords AS p2__meta_keywords,
p2.meta_description AS p2__meta_description,
p2.meta_visible_in_navigation AS p2__meta_visible_in_navigation,
p2.root_id AS p2__root_id,
p2.lft AS p2__lft,
p2.rgt AS p2__rgt,
p2.level AS p2__level,
d.id AS d__id,
d.name AS d__name,
d.latitude AS d__latitude,
d.longitude AS d__longitude,
d.introduction AS d__introduction,
d.description AS d__description,
d.thumbnail AS d__thumbnail,
d.path_id AS d__path_id,
p3.id AS p3__id,
p3.price AS p3__price,
p3.number_of_bedrooms AS p3__number_of_bedrooms,
p3.key_features AS p3__key_features,
p3.description AS p3__description,
p3.thumbnail AS p3__thumbnail,
p3.property_type_id AS p3__property_type_id,
p3.path_id AS p3__path_id
FROM path p,
path p2,
development d,
property p3
WHERE ( p.lft BETWEEN p2.lft AND p2.rgt
AND p.template_type = 'Property'
AND p2.level = node.level - 1
AND d.id = p2.object_id
AND p3.id = p.object_id )
导致此错误:
任何想法?我可以看到它应该是“AND p2.level = p.level - 1”,但它似乎并没有转换节点。
有什么想法吗?
答案 0 :(得分:1)
当您开始获得复杂的查询时,有时您不希望依赖于doctrine来生成您的SQL代码。更不用说你试图转换已经工作的查询以满足Doctrine的痛苦。
在这些情况下,我通常建议将查询作为SQL运行,而不是通过doctrine查询构建器传递它。