我在一个编译和有效工作的函数中有以下嵌套的Seq.map()调用:
|> Seq.map (fun (tradedOnKey : DateTime, portfolioSeq : seq<PortfolioId * seq<PortfolioFundRecord>>) ->
let pricedPortfoliosGroup =
portfolioSeq
|> Seq.map (fun (p : PortfolioId, spsf : (seq<PortfolioFundRecord>)) ->
let price =
spsf
|> Seq.map (fun (pfr : PortfolioFundRecord) -> pfr.Fund.ClosingPrice * float pfr.PortfolioWeight / 100.0)
|> Seq.reduce (+)
let topPortfolioFundRecord = spsf |> Seq.head
{ PortfolioId = p; Price = price; TradedOn = topPortfolioFundRecord.Fund.TradedOn }
)
(tradedOnKey, pricedPortfoliosGroup)
)
会提示以下lint警告:
Lint:
Seq.map f (Seq.map g x)
可能会被重构为Seq.map (g >>f) x
。
我相信这些前2个地图调用会提示警告:
|> Seq.map (fun (tradedOnKey : DateTime, portfolioSeq : seq<PortfolioId * seq<PortfolioFundRecord>>) ->
let pricedPortfoliosGroup =
portfolioSeq
|> Seq.map (fun (p : PortfolioId, spsf : (seq<PortfolioFundRecord>)) ->
但是我不知道如何重构它们,因为我的第二个参数是一个序列,我想&#34;转换它&#34;但不要压扁它。
你能建议一种方法吗?我还想找到一种方法来关闭针对该代码片段的lint警告,但电动工具似乎没有提供这样做的方法。
以下是完整性的全部功能:
let getPortfoliosPrices(dbFundsWithPortfolioFunds : (DbFunds * DbPortfolioFunds) Linq.IQueryable)(takenDays: int) =
let portfolioPrices =
dbFundsWithPortfolioFunds
|> Seq.collect(fun (f : DbFunds, fp : DbPortfolioFunds) ->
takenDays |> getStockPrices f.Symbol
|> Seq.map(fun(quote : FundQuote) ->
let portfolioFundRec = {PortfolioId = fp.PortfolioId; PortfolioWeight = fp.Weight; Fund = quote}
portfolioFundRec)
)
|> Seq.groupBy(fun (portfolioFundRec : PortfolioFundRecord) -> portfolioFundRec.Fund.TradedOn)
|> Seq.map(fun (tradedOnKey : DateTime, spfr : PortfolioFundRecord seq) ->
let gpfr = spfr |> Seq.groupBy (fun(pfr : PortfolioFundRecord)->pfr.PortfolioId)
(tradedOnKey, gpfr)
)
|> Seq.map (fun (tradedOnKey : DateTime, portfolioSeq : seq<PortfolioId * seq<PortfolioFundRecord>>) ->
let pricedPortfoliosGroup =
portfolioSeq
|> Seq.map (fun (p : PortfolioId, spsf : (seq<PortfolioFundRecord>)) ->
let price =
spsf
|> Seq.map (fun (pfr : PortfolioFundRecord) -> pfr.Fund.ClosingPrice * float pfr.PortfolioWeight / 100.0)
|> Seq.reduce (+)
let topPortfolioFundRecord = spsf |> Seq.head
{ PortfolioId = p; Price = price; TradedOn = topPortfolioFundRecord.Fund.TradedOn }
)
(tradedOnKey, pricedPortfoliosGroup)
)
portfolioPrices
答案 0 :(得分:5)
在您的第二个顶级Seq.map
中,您只是通过tradedOnKey
,并对您的序列执行某些操作。您可以通过执行以下操作将所有内容合并为一个:
dbFundsWithPortfolioFunds
|> Seq.collect(fun (f : DbFunds, fp : DbPortfolioFunds) ->
takenDays |> getStockPrices f.Symbol
|> Seq.map(fun(quote : FundQuote) ->
let portfolioFundRec = {PortfolioId = fp.PortfolioId; PortfolioWeight = fp.Weight; Fund = quote}
portfolioFundRec)
)
|> Seq.groupBy(fun portfolioFundRec-> portfolioFundRec.Fund.TradedOn)
|> Seq.map(fun (tradedOnKey, spfr) ->
let gpfr = spfr |> Seq.groupBy (fun pfr -> pfr.PortfolioId)
let pricedPortfoliosGroup =
gpfr
|> Seq.map (fun (p, spsf) ->
let price =
spsf
|> Seq.sumBy (fun pfr -> pfr.Fund.ClosingPrice * float pfr.PortfolioWeight / 100.0)
let topPortfolioFundRecord = spsf |> Seq.head
{ PortfolioId = p; Price = price; TradedOn = topPortfolioFundRecord.Fund.TradedOn }
)
(tradedOnKey, pricedPortfoliosGroup)
)
这应该消除警告(很难验证,因为我没有完整复制品的所有类型定义)。