Question

EDITED：我们如何采取以下方式

fields = [{"Name"=>"CONTACT.MAILADDRESS.LATITUDE", "dataName"=>"Pt_FieldDouble", "externalDataName"=>"number", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"10", "DisplayLabel"=>"Latitude", "Description"=>"Latitude", "id"=>"999505900000211"},
 {"Name"=>"CONTACT.MAILADDRESS.LONGITUDE", "dataName"=>"Pt_FieldDouble", "externalDataName"=>"number", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"11", "DisplayLabel"=>"Longitude", "Description"=>"Longitude", "id"=>"999505900000212"},
 {"Name"=>"CONTACT.STATE", "dataName"=>"Pt_FieldString", "externalDataName"=>"string", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"0", "DisplayLabel"=>"Status", "Description"=>"Active/Inactive", "id"=>"999505900000166"},
 {"Name"=>"XXSTATUS", "dataName"=>"Pt_FieldString", "externalDataName"=>"string", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"0", "DisplayLabel"=>"XStatus", "Description"=>"Active/Inactive", "id"=>"99950591200166"}] 

output = 
     [{"CONTACT" =>
        { "MAILADDRESS" =>
           { "Name" => "LATITUDE", "dataName"=>"Pt_FieldDouble", "externalDataName"=>"number", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"10", "DisplayLabel"=>"Latitude", "Description"=>"Latitude", "id"=>"999505900000211"},
           { "Name" => "LATITUDE", "dataName"=>"Pt_FieldDouble", "externalDataName"=>"number", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"11", "DisplayLabel"=>"Longitude", "Description"=>"Longitude", "id"=>"999505900000212"}},
        { "Name" =>"STATE", "dataName"=>"Pt_FieldString", "externalDataName"=>"string", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"0", "DisplayLabel"=>"Status", "Description"=>"Active/Inactive", "id"=>"999505900000166"}},
      { "Name" =>"XXSTATUS", "dataName"=>"Pt_FieldString", "externalDataName"=>"string", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"0", "DisplayLabel"=>"XStatus", "Description"=>"Active/Inactive", "id"=>"99950591200166"}]

我试过

fields.map {| i | {i [＆＃34;姓名＆＃34;] =＆gt; i.except（＆＃34;名称＆＃34;）}}

[{"CONTACT.MAILADDRESS.LATITUDE"=>{"dataName"=>"Pt_FieldDouble", "externalDataName"=>"number", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"10", "DisplayLabel"=>"Latitude", "Description"=>"Latitude", "id"=>"999505900000211"}},
{"CONTACT.MAILADDRESS.LONGITUDE"=>{"dataName"=>"Pt_FieldDouble", "externalDataName"=>"number", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"11", "DisplayLabel"=>"Longitude", "Description"=>"Longitude", "id"=>"999505900000212"}},
{"CONTACT.STATUS"=>{"dataName"=>"Pt_FieldString", "externalDataName"=>"string", "isRequired"=>"false", "isReadOnly"=>"false", "maxLength"=>"0", "DisplayLabel"=>"Status", "Description"=>"Active/Inactive", "id"=>"999505900000166"}}]

了解如何拆分键并将值放在一起

Answer 1

您想要的内容与Trie类似，因此您可以解析名称部分并使用each_with_object和inject创建嵌套哈希。这适用于任何嵌套深度：

[{
  "column1Value": "Country",
  "column2Value": "Value"
}, {
  "column1Value": "Flag",
  "column2Value": "Value"
}, {
  "column1Value": "Capital",
  "column2Value": "Value"
}, {
  "column1Value": "Region",
  "column2Value": "Value"
}, {
  "column1Value": "GPS",
  "column2Value": "Value"
}]

Answer 2

有点罗嗦，但你可以做......

 output = {}

 pointer = nil

 fields.each do |field|
  pointer = output
  sections = field['Name'].split('.').each do |section|
    pointer[section] ||= {}
    pointer = pointer[section]
  end
  pointer.merge!(field)
  pointer.delete('Name')
end 
output

用条件重新排列ruby哈希

2 个答案: