如何清除或删除或隐藏Framelayout的边框线？

Question

这里有一个framelayout周围的方形边框，我想在点击监听器上删除它 请为此提出任何合适的解决方案。

        ivFetchimage.setImageBitmap(bitmap);
        StickerImageView iv_sticker = new StickerImageView(getApplicationContext());
        iv_sticker.setImageDrawable(ivFetchimage.getDrawable());
        int getScreenWidth = Other.getScreenWidth(getApplicationContext()) / 2;
        FrameLayout.LayoutParams params = new FrameLayout.LayoutParams(getScreenWidth, getScreenWidth);
        params.gravity = Gravity.CENTER;
        iv_sticker.setLayoutParams(params);

        frameLayoutcanvas.removeAllViews();
        frameLayoutcanvas.addView(iv_sticker);

        frameLayoutcanvas.setVisibility(View.VISIBLE);
        frameLayoutcanvas.bringToFront();

这里有我的xml代码

<FrameLayout
        android:id="@+id/vg_canvas"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        >
        <ImageView
            android:id="@+id/fetchimage"
            android:layout_width="match_parent"
            android:layout_height="match_parent"
            android:adjustViewBounds="true"
            android:scaleType="fitXY"
            android:src="@drawable/profile" />

    </FrameLayout>

Answer 1

@chiragdulera这是我的意思：

<RelativeLayout
    android:layout_width="match_parent"
    android:layout_height="match_parent">
   <yourFrameLayout>
    <ImageView
        android:layout_width="match_parent"
        android:layout_height="match_parent"/>
   </yourFrameLayout>
    <View
        android:id="@+id/borderView"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:background="@drawable/transparent_background_outlet" />
</RelativeLayout>

drawable transparent_background_outlet看起来像：

<?xml version="1.0" encoding="utf-8"?>
    <shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="rectangle">
         <solid android:color="#00000000" />
         <stroke android:color="#000000" android:width="2dp"/>
    </shape>

现在设置可见或不可见的borderView，取决于你。