我有一种拍摄照片的方法,根据我的需要拍摄垂直形状的样本,横向拍摄并保存垂直照片,就像我希望进行锻炼练习一样,Activity称为ViewerActivity,它就在这里问题开始于在ImageView中显示水平样本的照片:/他正在阅读并且有一个类ExifInterface允许控制图像的方向,但在显示时图像仍然是水平的
本课程负责发送照片。
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == REQUEST_IMAGE_CAPTURE && resultCode == Activity.RESULT_OK) {
try {
ExifInterface exifInterface = new ExifInterface(photoFile.getAbsolutePath());
int valor = exifInterface.getAttributeInt(ExifInterface.TAG_ORIENTATION, ExifInterface.ORIENTATION_NORMAL);
switch (valor) {
case ExifInterface.ORIENTATION_ROTATE_90:
orientation = 90;
break;
case ExifInterface.ORIENTATION_ROTATE_180:
orientation = 180;
break;
case ExifInterface.ORIENTATION_ROTATE_270:
orientation = 270;
break;
}
} catch (Exception e) {
Log.d("mensaje", e.toString());
}
Intent i = new Intent(this, ViewerActivity.class);
i.putExtra(EXTRA_PHOTO_PATH, photoFile.getAbsolutePath());
i.putExtra(EXTRA_PHOTO_ORIENTATION, orientation);
i.putExtra(EXTRA_PHOTO_EDIT, false);
startActivityForResult(i, 10);
此ViewerActivity类显示照片,然后发送
private void sendPicture() {
Intent intent = new Intent();
intent.putExtra("path", localPath);
intent.putExtra("orientation",orientation);
setResult(Activity.RESULT_OK, intent);
finish();
}
答案 0 :(得分:1)
使用RotateLayout
,完整的课程和样本可在以下链接中找到。
https://github.com/rongi/rotate-layout
与使用RotateLayout
制作新的轮播Bitmap
相比,使用Matrix
相当容易,内存消耗也更少。
将ImageView
置于RotateLayout
内,如下面的代码
<com.github.rongi.rotate_layout.layout.RotateLayout
android:id="@+id/form3_container"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
app:angle="180">
<ImageView
android:id="@+id/imageview"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
/>
</com.github.rongi.rotate_layout.layout.RotateLayout>
并将orientation
的{{1}}值设置为ExifInterface
中的angle
属性。RotateLayout
已旋转,您无需担心位图或ImageView
ExifInterface
的任何其他内容。
您可以将角度值从java代码动态设置为orientation
对象,如下所示
RotateLayout
答案 1 :(得分:0)
试试这个:
BitmapFactory.Options bounds = new BitmapFactory.Options();
bounds.inJustDecodeBounds = true;
BitmapFactory.decodeFile(file, bounds);
BitmapFactory.Options opts = new BitmapFactory.Options();
Bitmap bm = BitmapFactory.decodeFile(file, opts);
ExifInterface exif = new ExifInterface(file);
String orientString = exif.getAttribute(ExifInterface.TAG_ORIENTATION);
int orientation = orientString != null ? Integer.parseInt(orientString) : ExifInterface.ORIENTATION_NORMAL;
int rotationAngle = 0;
if (orientation == ExifInterface.ORIENTATION_ROTATE_90) rotationAngle = 90;
if (orientation == ExifInterface.ORIENTATION_ROTATE_180) rotationAngle = 180;
if (orientation == ExifInterface.ORIENTATION_ROTATE_270) rotationAngle = 270;
Matrix matrix = new Matrix();
matrix.setRotate(rotationAngle, (float) bm.getWidth() / 2, (float) bm.getHeight() / 2);
Bitmap rotatedBitmap = Bitmap.createBitmap(bm, 0, 0, bounds.outWidth, bounds.outHeight, matrix, true);`
其中file
是图像文件的名称。
答案 2 :(得分:0)
try {
File f = new File(imagePath);
ExifInterface exif = new ExifInterface(f.getPath());
int orientation = exif.getAttributeInt(
ExifInterface.TAG_ORIENTATION,
ExifInterface.ORIENTATION_NORMAL);
int angle = 0;
if (orientation == ExifInterface.ORIENTATION_ROTATE_90) {
angle = 90;
} else if (orientation == ExifInterface.ORIENTATION_ROTATE_180) {
angle = 180;
} else if (orientation == ExifInterface.ORIENTATION_ROTATE_270) {
angle = 270;
}
Matrix mat = new Matrix();
mat.postRotate(angle);
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 2;
Bitmap bmp = BitmapFactory.decodeStream(new FileInputStream(f),
null, options);
bitmap = Bitmap.createBitmap(bmp, 0, 0, bmp.getWidth(),
bmp.getHeight(), mat, true);
ByteArrayOutputStream outstudentstreamOutputStream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.PNG, 100,
outstudentstreamOutputStream);
imageView.setImageBitmap(bitmap);
} catch (IOException e) {
Log.w("TAG", "-- Error in setting image");
} catch (OutOfMemoryError oom) {
Log.w("TAG", "-- OOM Error in setting image");
}
在onActivityResult
中获取imagepath时尝试此操作答案 3 :(得分:0)
试试吧
function myhandler(event) {
function(x, y); // Still not a valid name
}
div.onclick = myhandler;