我正在尝试使用python打开网页源代码，但我一直在标题中收到错误。我可以发布完整的错误，但它很长，我认为这就足够了。我一直试图弄清楚这几个小时，但我遇到的解决方案要么不起作用，要么对我没有意义。
我导入了urllib.request和urllib.parse。我打开网页代码的代码如下：
请求打开网页来源
source_request = urllib.request.Request("secure website") #Opens the web page source_open = urllib.request.urlopen('https://www.ohio.edu/engineering/about/people/') #Reads all the data into a list(?) source_code = source_open.read() #Converts data into a string source_string = source_code.decode()
如果这很重要，我也在使用python3。任何帮助将不胜感激，谢谢！
编辑：
完全错误
Traceback (most recent call last):
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 1318, in do_open
encode_chunked=req.has_header('Transfer-encoding'))
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py", line 1239, in request
self._send_request(method, url, body, headers, encode_chunked)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py", line 1285, in _send_request
self.endheaders(body, encode_chunked=encode_chunked)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py", line 1234, in endheaders
self._send_output(message_body, encode_chunked=encode_chunked)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py", line 1026, in _send_output
self.send(msg)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py", line 964, in send
self.connect()
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py", line 1400, in connect
server_hostname=server_hostname)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ssl.py", line 401, in wrap_socket
_context=self, _session=session)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ssl.py", line 808, in __init__
self.do_handshake()
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ssl.py", line 1061, in do_handshake
self._sslobj.do_handshake()
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ssl.py", line 683, in do_handshake
self._sslobj.do_handshake()
ssl.SSLError: [SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:749)
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "hw3.py", line 53, in <module>
main()
File "hw3.py", line 37, in main
source_open = urllib.request.urlopen('https://www.ohio.edu/engineering/about/people/')
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 223, in urlopen
return opener.open(url, data, timeout)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 526, in open
response = self._open(req, data)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 544, in _open
'_open', req)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 504, in _call_chain
result = func(*args)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 1361, in https_open
context=self._context, check_hostname=self._check_hostname)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py", line 1320, in do_open
raise URLError(err)
urllib.error.URLError: <urlopen error [SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:749)>
所以，我相当肯定这个问题源于安全与不安全的网站。有没有办法绕过这个？
编辑：
我找到了解决方案。新代码如下：
#import ssl above this, obviously
context = ssl._create_unverified_context()
source_open = urllib.request.urlopen('https://www.ohio.edu/engineering/about/people/', context = context)
source_code = source_open.read()
source_string = source_code.decode()