如何确保python dict键是小写的?

时间:2010-11-19 09:31:04

标签: python json simplejson django-piston

我有一个dict,我想使用simplejson转换为JSON。

如何确保我的dict的所有键都是小写的?

    {
        "DISTANCE": 17.059918745802999, 
        "name": "Foo Bar", 
        "Restaurant": {
            "name": "Foo Bar", 
            "full_address": {
                "country": "France", 
                "street": "Foo Bar", 
                "zip_code": "68190", 
                "city": "UNGERSHEIM"
            }, 
            "phone": "+33.389624300", 
            "longitude": "7.3064454", 
            "latitude": "47.8769091", 
            "id": "538"
        }, 
        "price": "", 
        "composition": "", 
        "profils": {}, 
        "type_menu": "", 
        "ID": ""
    },
编辑:谢谢大家看看我的问题,很抱歉,我没有详细解释为什么我想要这个。这是修补JSONEmitter的{​​{1}}。

8 个答案:

答案 0 :(得分:23)

>>> d = {"your": "DATA", "FROM": "above"}
>>> dict((k.lower(), v) for k, v in d.iteritems())
{'from': 'above', 'your': 'DATA'}
>>> def lower_keys(x):
...   if isinstance(x, list):
...     return [lower_keys(v) for v in x]
...   elif isinstance(x, dict):
...     return dict((k.lower(), lower_keys(v)) for k, v in x.iteritems())
...   else:
...     return x
...
>>> lower_keys({"NESTED": {"ANSWER": 42}})
{'nested': {'answer': 42}}

答案 1 :(得分:8)

以下是禁止设置小写密钥的解决方案:

class LowerCaseDict(dict):
    def __setitem__(self, key, val):
        if not key.islower():
            raise TypeError, "%s key must be lowercase" % key
        dict.__setitem__(self, key, val)

ld = LowerCaseDict()
ld['g']='g'

答案 2 :(得分:4)

这是我的解决方案:

def lower_key(in_dict):
    if type(in_dict) is dict:
        out_dict = {}
        for key, item in in_dict.items():
            out_dict[key.lower()] = lower_key(item)
        return out_dict
    elif type(in_dict) is list:
        return [lower_key(obj) for obj in in_dict]
    else:
        return in_dict

答案 3 :(得分:4)

由于您没有清楚地提到您想要做什么:

将所有键转换为小写:

>>> y = dict((k.lower(), v) for k, v in x.iteritems())

检查按键:

>>> for k in x.iterkeys():
    if k.islower():
        print k, 'True'
    else:
        print k, 'False'

答案 4 :(得分:2)

如果你只想检查,如果它们都是小写的(你的措辞,使用“确保”,不清楚,但我怀疑这不是你想要的),你可以做紧凑的一行:

all(k.islower() for k in x.iterkeys())

答案 5 :(得分:2)

这是一个完整的解决方案

from requests import CaseInsensitiveDict

或者如果你想看代码:

class CaseInsensitiveDict(dict):

    """Basic case insensitive dict with strings only keys."""

    proxy = {}

    def __init__(self, data):
        self.proxy = dict((k.lower(), k) for k in data)
        for k in data:
            self[k] = data[k]

    def __contains__(self, k):
        return k.lower() in self.proxy

    def __delitem__(self, k):
        key = self.proxy[k.lower()]
        super(CaseInsensitiveDict, self).__delitem__(key)
        del self.proxy[k.lower()]

    def __getitem__(self, k):
        key = self.proxy[k.lower()]
        return super(CaseInsensitiveDict, self).__getitem__(key)

    def get(self, k, default=None):
        return self[k] if k in self else default

    def __setitem__(self, k, v):
        super(CaseInsensitiveDict, self).__setitem__(k, v)
        self.proxy[k.lower()] = k

答案 6 :(得分:1)

您可以使用python-benedict(一个dict子类)并标准化您的实例,以将所有字符串键转换为snake_case

from benedict import benedict

d = benedict({
    "DISTANCE": 17.059918745802999, 
    "name": "Foo Bar", 
    "Restaurant": {
        "name": "Foo Bar", 
        "full_address": {
            "country": "France", 
            "street": "Foo Bar", 
            "zip_code": "68190", 
            "city": "UNGERSHEIM"
        }, 
        "phone": "+33.389624300", 
        "longitude": "7.3064454", 
        "latitude": "47.8769091", 
        "id": "538"
    }, 
    "price": "", 
    "composition": "", 
    "profils": {}, 
    "type_menu": "", 
    "ID": ""
})

# convert all string keys to snake_case (nested dict keys included)
d.standardize()

,您的dict将变为:

{
    "distance": 17.059918745802999, 
    "name": "Foo Bar", 
    "restaurant": {
        "name": "Foo Bar", 
        "full_address": {
            "country": "France", 
            "street": "Foo Bar", 
            "zip_code": "68190", 
            "city": "UNGERSHEIM"
        }, 
        "phone": "+33.389624300", 
        "longitude": "7.3064454", 
        "latitude": "47.8769091", 
        "id": "538"
    }, 
    "price": "", 
    "composition": "", 
    "profils": {}, 
    "type_menu": "", 
    "id": ""
})

安装:pip install python-benedict

文档:https://github.com/fabiocaccamo/python-benedict

答案 7 :(得分:0)

用于处理值的另一种适应方法:

//1
{"id":1,"random":0.7818309762014325}

//2
{"flattened":false,"id":2}