我在这段代码上有错误。我不能像我想要的那样得到数据库的结果
<?php
$conn = mysqli_connect('localhost', '****', '****', 'kj1irpfd_bkintra');
$sql="SELECT * FROM `picagem`";
$query=mysqli_query($conn, $sql);
$to = "ricardo.ribeiro@bluekids.pt";
$subject = "order information!";
$message = 'thanks :) this is bank account
<table>
<tr>
<th>Numero</th>
<th>datelogin</th>
<th>datelogout</th>
<th>horario</th>
</tr>';
while($arraybank=mysqli_fetch_array($conn, $query)){
$message .='
<tr>
<td>'.$arraybank['numOper'].'</td>
<td>'.$arraybank['datelogin'].'</td>
<td>'.$arraybank['datelogout'] .'</td>
<td>'.$arraybank['horario'] .'</td>
</tr>';
}
$message .= 'id order :'.$numOper.',shop again! ';
$headers = 'MIME-Version: 1.0' . "\r\n".
'Content-Type: text/html; charset=ISO-8859-1' . "\r\n".
'From: shoesshe <cs@shoesshe.com>' . "\r\n" .
'Reply-To: shoesshe <cs@shoesshe.com>' . "\r\n" .
'X-Mailer: PHP/' . phpversion();
mail($to, $subject, $message, $headers);
我该怎么办?怎么了?
我在这里结果,我的数据库有结果而不在这里显示。为什么呢?!