如何在google blogger的相同标签中打开内部链接(标签链接)

时间:2017-02-14 19:00:29

标签: html blogger

我的博客网址:https://fashionindiar.blogspot.com

我无法在相同的标签/窗口中打开独立主页上的标签链接。实际上,我错误地检查了之前菜单栏上链接按钮下的相应复选框,之后我无法恢复。但是,复选框显示未选中。

另外,请注意我的主页上有社交媒体按钮,应该在新标签/窗口中打开(我已经激活了链接按钮下的相应选项,我不想篡改它)。

请帮我打开同一标签/窗口中的所有标签链接(在我的主页上),而不是任何新标签链接。

期待您的回复。

谢谢。

Shampa Sengupta

1 个答案:

答案 0 :(得分:0)

要在点击相同的框架中打开链接,请从Error:warning: Ignoring InnerClasses attribute for an anonymous inner class Error:(org.codehaus.stax2.XMLStreamLocation2$1) that doesn't come with an Error:associated EnclosingMethod attribute. This class was probably produced by a Error:compiler that did not target the modern .class file format. The recommended Error:solution is to recompile the class from source, using an up-to-date compiler Error:and without specifying any "-target" type options. The consequence of ignoring Error:this warning is that reflective operations on this class will incorrectly Error:indicate that it is *not* an inner class. 代码中删除属性target="_blank",或将其更改为<a>