消息：尝试获取非对象的属性

Question

我已经检查了其他重复的标题，但这并没有给我答案我的问题。我有这个错误，我仍然无法修复：

当我点击agent_dashboard（侧面）时，我注意到这个错误。

txtDisplayName = <div style="border:1px solid #990000;padding-left:20px;margin:0 0 10px 0;">

<h4>A PHP Error was encountered</h4>

<p>Severity: Notice</p>
<p>Message:  Trying to get property of non-object</p>
<p>Filename: agent/dashboard.php</p>
<p>Line Number: 28</p>

</div>;
        txtPrivateIdentity = <div style="border:1px solid #990000;padding-left:20px;margin:0 0 10px 0;">

<h4>A PHP Error was encountered</h4>

<p>Severity: Notice</p>
<p>Message:  Trying to get property of non-object</p>
<p>Filename: agent/dashboard.php</p>
<p>Line Number: 29</p>

</div>;
        txtPublicIdentity = <div style="border:1px solid #990000;padding-left:20px;margin:0 0 10px 0;">

<h4>A PHP Error was encountered</h4>

<p>Severity: Notice</p>
<p>Message:  Trying to get property of non-object</p>
<p>Filename: agent/dashboard.php</p>
<p>Line Number: 30</p>

</div>;
        txtPassword = <div style="border:1px solid #990000;padding-left:20px;margin:0 0 10px 0;">

<h4>A PHP Error was encountered</h4>

<p>Severity: Notice</p>
<p>Message:  Trying to get property of non-object</p>
<p>Filename: agent/dashboard.php</p>
<p>Line Number: 31</p>

</div>;
        txtRealm = <div style="border:1px solid #990000;padding-left:20px;margin:0 0 10px 0;">

<h4>A PHP Error was encountered</h4>

<p>Severity: Notice</p>
<p>Message:  Trying to get property of non-object</p>
<p>Filename: agent/dashboard.php</p>
<p>Line Number: 32</p>

</div>;

这是我的Controller Main_Controller / agent_dashboard

public function agent_dashboard() {
  $this->load->library('session');
  $user = $this - > session - > userdata('user');
  $data['user'] = $this - > Model - > each_user_data($user);
  //var_dump($data);
  $this - > load - > view('agent/dashboard', $data);
}

当我var_dump（$ data）时，我可以看到数据已经传递给View，这是我的模型Model / each_user_data

public function each_user_data($user){
        $this->db->select('user');
        // $this->db->select('user_level');
        $this->db->select('full_name');
        $this->db->select('pass');
        $this->db->select('private_identity');
        $this->db->select('public_identity');
        $this->db->select('realm');
        $this->db->where('user', $user);
        $query = $this->db->get('t_users');
        return $query->row();
    }

最后这是我的查看代理/仪表板，我在这上面使用了jquery。

<?php foreach($user as $u) {?>
            var txtDisplayName;
            var txtPrivateIdentity;
            var txtPublicIdentity;
            var txtPassword;
            var txtRealm;


        txtDisplayName = <?php echo $u->user; ?>;
        txtPrivateIdentity = <?php echo $u->private_identity; ?>;
        txtPublicIdentity = <?php echo $u->public_identity; ?>;
        txtPassword = <?php echo $u->pass; ?>;
        txtRealm = <?php echo $u->realm; ?>;

        <?php } ?>

如何解决这个问题？

Answer 1

user是一个数组，您将其视为一个对象。这就是它给出错误的原因，试图获取非对象的属性（在这种情况下，是一个数组）。 试试：

 $u['user'] 

 $u['private_identity'] ...