Question

我正在使用Django 1.10并尝试使用异常中间件捕获所有异常。

以下代码导致内部服务器错误：

mw_instance = middleware(handler)
TypeError: object() takes no parameters

views.py

from django.http import HttpResponse

def my_view(request):
    x = 1/0 # cause an exception
    return HttpResponse("ok")

settings.py

MIDDLEWARE = [
    'django.middleware.security.SecurityMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.common.CommonMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    'django.middleware.clickjacking.XFrameOptionsMiddleware',
    'myproject.middleware.ExceptionMiddleware',  

]

middleware.py

from django.http import HttpResponse

class ExceptionMiddleware(object):
    def process_exception(self, request, exception): 
        return HttpResponse("in exception")

我已经看到这些object() takes no parameters in django 1.10和其他问题在讨论中间件与中间件_类，但我不确定这是如何适用于这种情况，或者我实际需要改变以解决问题。

Answer 1

由于您使用的是新的MIDDLEWARE设置，因此您的中间件类必须接受get_response参数：https://docs.djangoproject.com/en/1.10/topics/http/middleware/#writing-your-own-middleware

你可以写这样的课：

from django.http import HttpResponse

class ExceptionMiddleware(object):
    def __init__(self, get_response):
        self.get_response = get_response

    def __call__(self, request):
        return self.get_response(request)

    def process_exception(self, request, exception): 
        return HttpResponse("in exception")

您还可以使用MiddlewareMixin使您的中间件与1.10之前和1.10之后的Django版本兼容：https://docs.djangoproject.com/en/1.10/topics/http/middleware/#upgrading-pre-django-1-10-style-middleware

from django.http import HttpResponse
from django.utils.deprecation import MiddlewareMixin

class ExceptionMiddleware(MiddlewareMixin):
    def process_exception(self, request, exception):
        return HttpResponse("in exception")

Django异常中间件：TypeError：object（）不带参数

1 个答案: