Question

如何通过PHP将SELECT datepart(ww,[Promised Ship Date]) as weekno ,[Item ID] ,[UNITOFMEASURE] ,[UNITOFMEASURECONV] as ConvQTY ,count(*) as Orders FROM SalesHistory vw inner join ITEMTABLE IT on IT.itemcode = vw.[Item Id] where [Promised Ship Date] >= '2016-01-01' and [Promised Ship Date] < '2016-02-01' and [UDF_MIN_SALES_UNIT] = 'Each' group by datepart(ww,[Promised Ship Date]),[item id],[unitofmeasure],[UNITOFMEASURECONV] order by weekno,[item id]替换为<%= text_field_tag :email, nil, placeholder: 'Email' %>来显示和隐藏一些电话号码？

EX：

09350943256 - ＆gt; 0935 *** 3256
09119822432 - ＆gt; 0911 *** 2432
09215421597 - ＆gt; 0921 *** 1597
...

热门PHP代码的结果如下：0935***3256但我希望结果为：$number = '09350943256'; echo str_pad(substr($number, -4), strlen($number), '*', STR_PAD_LEFT);

怎么回事？

Answer 1

你可以这样使用substr和concat

假设您的$ number是12位数

echo  substr($number, 0, 4) . '****' . substr($number,  -4);

Answer 2

简而言之：

$phone = 01133597084;
$maskedPhone = substr($user->phone, 0, 4) . "****" . substr($user->phone, 7, 4);

<块引用>

// $maskedPhone 的输出是 0113****7084

Answer 3

您可以使用substr()来获取前4个和后4个，并在中间手动添加4个*，并将它们全部放在一个字符串中。

$phone = "09350943256";
$result = substr($phone, 0, 4);
$result .= "****";
$result .= substr($phone, 7, 4);
echo $result;

上面会输出

0935 **** 3256

Live demo

Answer 4

<?php  
$phone='05325225990';

function stars($phone)
{
	$times=strlen(trim(substr($phone,4,5)));
	$star='';
	for ($i=0; $i <$times ; $i++) { 
		$star.='*';
	}
	return $star;
}

$result=str_replace(substr($phone, 4,5), stars($phone), $phone);
echo $result;

?>

0532 ***** 90

Answer 5

您可以使用substr_replace()功能

<?php
$mobnum ="09350943256";
for($i=4;$i<7;$i++)
{
  $mobnum = substr_replace($mobnum,"*",$i,1);
}
echo $mobnum;
?>

Answer 6

我建议使用这种“声明式”解决方案，而不是计算指数的数学运算：

<?php

$number='0123456789';
$matches=[];
preg_match('/(\\d{4})(\\d+)(\\d{4})/', $number, $matches);
$result=$matches[1].str_repeat('*',strlen($matches[2])).$matches[2];
print($result);

?>

隐藏电话号码的号码

6 个答案: