Question

我是Selenium WebDriver测试的新手，我尝试在工作中使用它。我尝试了许多选择器，xpath等组合，但我无法超越它。我在stackoverflow上搜索了许多类似的主题，遗憾的是没有预期的结果。我需要的是能够点击“NO SERVICE”按钮（一个href）。当我尝试时，我不断收到错误，这个元素不可见。当我尝试使用“wait”来处理此错误时，我不断收到另一个错误“预期条件失败：等待元素的可见性......”。我做错了什么？

我的代码：

    WebDriverWait waitWait = new WebDriverWait(driver, 40);     
    waitWait.until(ExpectedConditions.visibilityOfElementLocated(By.className("withoutService")));      
    WebElement x = driver.findElement(By.className("withoutService"));
    x.click();

以及来自网页的html代码段：

<div id="fancybox-outer">
    <div id="fancybox-content">
        <div style="width:auto;position:relative;">
            <div id="serviceReminder" style="width: 765px">
                <form id="serviceReminderFrom" method="post">
                    <div class="homeMessage">
                        <div class="innerMessage">
                            <input type="hidden" id="serviceToAddReminderFromAction" name="F_ACTION" value="">
                            <input type="hidden" id="itemsWithServices" name="itemsWithServices" value="">
                            <input type="hidden" name="eventTypeName" value="Something">
                                <div class="ServicesDelivery"><span class="disable-button"></span>
                                    <a href="javaScript:void(0);" rel="3" class="withoutService btn btn-fourth" onclick="registerButtonClickOnPopup('NO SERVICE'); setTimeout(function(){registerButtonClickOnPopup('NO SERVICE');},400);">NO SERVICE</a>
                                    <a href="javascript:void(0)" rel="1" class="next js-tooltip btn btn-second" onclick="registerButtonClickOnPopup('ADD SERVICE'); setTimeout(function(){registerButtonClickOnPopup('ADD SERVICE');},400);">ADD SERVICE</a>
                            <div class="none">
                            </div>
                            <div class="clear"></div>
                        </div>
                    </div>
                </div>
            </form>
        </div></div></div><a id="fancybox-close" style="display: inline;"></a><div id="fancybox-title" class="" style="display: none;">
        </div><a href="javascript:;" id="fancybox-left"><span class="fancy-ico" id="fancybox-left-ico"></span></a><a href="javascript:;" id="fancybox-right"><span class="fancy-ico" id="fancybox-right-ico"></span></a></div>

Answer 1

您的定位器By.className("withoutService")可以匹配多个元素。您需要更具体的选择器。请尝试以下代码：

WebDriverWait waitWait = new WebDriverWait(driver, 40);     
WebElement x = waitWait.until(ExpectedConditions.elementToBeClickable(By.linkText("NO SERVICE")));      
x.click();

Answer 2

尝试以下XPath：

//a[contains(@class, 'withoutService')]

完整代码：

WebDriverWait waitWait = new WebDriverWait(driver, 40);     
WebElement x = waitWait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//a[contains(@class, 'withoutService')]")));     
x.click();

如果上面的代码不起作用，那么元素可能在iframe内。请查看我的详细答案here。

Selenium WebDriver Java - 元素不可见

2 个答案: