Question

我有一组应该取出的数据，应按以下顺序准备报告

Last Name      First Name      Location
Blake          James           101007
fusio          Wiko            101008 
                     100 Total

FAROMOJU       BANKOLE         303315
Gibbs          Rhonda          303315
Greene         Leette          303315
                     331 Total

......
............

我们可以看到 3个字母代码 [从位置代码中提取 - CONCAT （SUBSTR（COLUMN3,3,3），'Total'）]在所有位置设置之后。我只是想出去获取报告，除了位置代码的降序外，它工作正常。它使用“位置”进行排序，然后将其变为3个字母代码而不是使用完整数字代码。所以在结果中，降序不能正常工作。请给我一个解决方案，

我正在附加我的代码，

******************************************************

FUNCTION GET_ACTY_SUMMARY(V_STARTDATE IN DATE,V_ENDDATE IN DATE)
RETURN TEMP_OUTPUT_TABLE PIPELINED IS
CURSOR ACTY_SUMMARY IS

/* The query fetches the report field grouped by First Name,Last Name
and Location.*/

   SELECT
          COLUMN1 AS LASTNAME,
          COLUMN2 AS FIRSTNAME,
          COLUMN3 AS LOCATION,
          SUM(COLUMN4) AS ACTIVITYNM1,
          SUM(COLUMN5) AS ACTIVITYNM2,
          SUM(COLUMN6) AS ACTIVITYNM3,
          SUM(COLUMN7) AS ACTIVITYNM4,
          SUM(COLUMN8) AS ACTIVITYNM5,
          SUM(COLUMN9) AS REG_HRS,
          SUM(COLUMN10) AS OT_HRS,
          SUM(COLUMN11) AS TOTAL_HRS,
          SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE

  FROM
  TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE))
  GROUP BY
   COLUMN1,
   COLUMN2,
   COLUMN3


  UNION

  SELECT NULL,
       NULL,
       CONCAT(SUBSTR(COLUMN3,3,3),'Total'),
       SUM(COLUMN4) AS ACTIVITYNM1,
       SUM(COLUMN5) AS ACTIVITYNM2,
       SUM(COLUMN6) AS ACTIVITYNM3,
       SUM(COLUMN7) AS ACTIVITYNM4,
       SUM(COLUMN8) AS ACTIVITYNM5,
       SUM(COLUMN9) AS REG_HRS,
       SUM(COLUMN10) AS OT_HRS,
       SUM(COLUMN11) AS TOTAL_HRS,
       SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE

  FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE))
  GROUP BY COLUMN3
  UNION

  SELECT NULL,
       NULL,
       'Total',
       SUM(COLUMN4) AS ACTIVITYNM1,
       SUM(COLUMN5) AS ACTIVITYNM2,
       SUM(COLUMN6) AS ACTIVITYNM3,
       SUM(COLUMN7) AS ACTIVITYNM4,
       SUM(COLUMN8) AS ACTIVITYNM5,
       SUM(COLUMN9) AS REG_HRS,
       SUM(COLUMN10) AS OT_HRS,
       SUM(COLUMN11) AS TOTAL_HRS,
       SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE

  FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE))


  ORDER BY 3 desc ;

GAS ACTY_SUMMARY%ROWTYPE;

/*Intialize the table output format with NULL.*/

TT TEMP_OUTPUT_FORMAT := INITIALIZE_TABLE_FORMAT();
  BEGIN
  OPEN ACTY_SUMMARY;
  FETCH ACTY_SUMMARY INTO GAS;
    WHILE ACTY_SUMMARY%FOUND LOOP
      BEGIN
        TT.COLUMN1 := GAS.LASTNAME;
        TT.COLUMN2 := GAS.FIRSTNAME;
        TT.COLUMN3 := GAS.LOCATION;
        TT.COLUMN4 := GAS.ACTIVITYNM1;
        TT.COLUMN5 := GAS.ACTIVITYNM2;
        TT.COLUMN6 := GAS.ACTIVITYNM3;
        TT.COLUMN7 := GAS.ACTIVITYNM4;
        TT.COLUMN8 := GAS.ACTIVITYNM5;
        TT.COLUMN9 := GAS.REG_HRS;
       TT.COLUMN10 := GAS.OT_HRS;
       TT.COLUMN11 := GAS.TOTAL_HRS;
       TT.COLUMN12 := GAS.PRODUCTIVITY_PERCENTAGE;
       PIPE ROW(TT);
     END;
    FETCH ACTY_SUMMARY INTO GAS;
   END LOOP;
  CLOSE ACTY_SUMMARY;
  RETURN;
END GET_ACTY_SUMMARY;

END GEHC_ACTY_REPT_PKG;


******************************************************

由于阿南德

Answer 1

我建议您将查询更改为

   SELECT 
          COLUMN1 AS LASTNAME, 
          COLUMN2 AS FIRSTNAME, 
          COLUMN3 AS LOCATION,
          COLUMN3 AS FULL_LOCATION,
          SUM(COLUMN4) AS ACTIVITYNM1, 
          SUM(COLUMN5) AS ACTIVITYNM2, 
          SUM(COLUMN6) AS ACTIVITYNM3, 
          SUM(COLUMN7) AS ACTIVITYNM4, 
          SUM(COLUMN8) AS ACTIVITYNM5, 
          SUM(COLUMN9) AS REG_HRS, 
          SUM(COLUMN10) AS OT_HRS, 
          SUM(COLUMN11) AS TOTAL_HRS, 
          SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 
  FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
  GROUP BY 
   COLUMN1, 
   COLUMN2, 
   COLUMN3
UNION ALL
  SELECT NULL, 
       NULL, 
       CONCAT(SUBSTR(COLUMN3,3,3),'Total'),
       COLUMN3 AS FULL_LOCATION,
       SUM(COLUMN4) AS ACTIVITYNM1, 
       SUM(COLUMN5) AS ACTIVITYNM2, 
       SUM(COLUMN6) AS ACTIVITYNM3, 
       SUM(COLUMN7) AS ACTIVITYNM4, 
       SUM(COLUMN8) AS ACTIVITYNM5, 
       SUM(COLUMN9) AS REG_HRS, 
       SUM(COLUMN10) AS OT_HRS, 
       SUM(COLUMN11) AS TOTAL_HRS, 
       SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 
  FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
  GROUP BY COLUMN3 
UNION ALL
  SELECT NULL, 
       NULL, 
       'Total',
       'Total' AS FULL_LOCATION,
       SUM(COLUMN4) AS ACTIVITYNM1, 
       SUM(COLUMN5) AS ACTIVITYNM2, 
       SUM(COLUMN6) AS ACTIVITYNM3, 
       SUM(COLUMN7) AS ACTIVITYNM4, 
       SUM(COLUMN8) AS ACTIVITYNM5, 
       SUM(COLUMN9) AS REG_HRS, 
       SUM(COLUMN10) AS OT_HRS, 
       SUM(COLUMN11) AS TOTAL_HRS, 
       SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 
  FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
  ORDER BY 4 DESC;

我们在这里要做的是在查询中添加完整的位置（数据中的COLUMN3，如果我正确地读取原始查询），以便排序可以基于它。您可能需要更改GROUP BY - 我不确定并且没有可用于测试的数据。但那是基本的想法。

分享并享受。

Answer 2

我建议查看分组集，而不是一起使用unioning数据。分组集（以及CUBE和ROLLUP）是在多个级别聚合数据的方法，这就是您似乎正在做的事情。使用分组集将获得您要查找的数据。

为了对数据进行排序，您需要在order by子句中添加其他列。我使用的grouping_id（）函数返回一个数字（0或1），具体取决于它是否为给定表达式的'superaggregate'行。这些'superaggregate'行是与总计和小计相关的附加行。我正在对数据进行排序以及该列是否为超级聚合。

认为你应该能够做到这样的事情：

SELECT 
  COLUMN1 AS LASTNAME, 
  COLUMN2 AS FIRSTNAME, 
  case 
    when grouping_id(column3, substr(column3,3,3)) = 3 then 'Total'
    when grouping_id(column3, substr(column3,3,3)) = 2 
      then substr(column3,3,3) ||' Total'
    else column3 end as location,
  SUM(COLUMN4) AS ACTIVITYNM1, 
  SUM(COLUMN5) AS ACTIVITYNM2, 
  SUM(COLUMN6) AS ACTIVITYNM3, 
  SUM(COLUMN7) AS ACTIVITYNM4, 
  SUM(COLUMN8) AS ACTIVITYNM5, 
  SUM(COLUMN9) AS REG_HRS, 
  SUM(COLUMN10) AS OT_HRS, 
  SUM(COLUMN11) AS TOTAL_HRS, 
  SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 
FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
GROUP BY grouping sets ((),  (substr(column3,3,3)), 
    (COLUMN1,COLUMN2,COLUMN3, substr(column3,3,3)))
order by 
  grouping_id(substr(column3,3,3)), 
  substr(column3,3,3) desc, 
  grouping_id(column3, substr(column3,3,3)), 
  column3 desc

希望能更快地运行并做你想做的事。我可能已经使order by子句比必要的更复杂，但它应该做你需要的。

PLSQL上的ORDER BY问题

2 个答案: