Question

只有在父级和子级之间没有文本时，我才需要将所有子内联样式传递给父级。

<span style="text from style"> <!-- this don't recive the childs' style because there are "cccc" -->
        cccc
        <span style="text from style"> <!-- this span recive the style of his child because there aren't plain text between them --> 
          <span style="text from style">
             bbb
          </span>
        </span>
</span>

我将子项样式传递给父项但我无法检查标记之后是否有文本

这是我的剧本：

currentElement.find('span').each(function(){
                        var $padreSpan = jQuery(this); //get the parent span
                        jQuery(this).find('span').each(function(){ //pass by all span child
                            var styleChildren = jQuery(this).attr('style'); //get them style
                            $padreSpan.attr('style', $padreSpan.attr('style')+ ";" + styleChildren+";"); //set style child to parent
                        });
                        $padreSpan.html(
                                $padreSpan.html().replace(/<span\b[^>]*>/gi,"").replace(/<\/span>/gi,"")
                        ); //clear child spans
                    });

我该怎么办？

Answer 1

var parent=$('span');    
var children=$(parent).children();

如果删除所有子节点，剩下的就是文本。因此：

var backup=$(children).remove();
var text=$(parent).text().trim();
var length=text.length;
if(length>0){
//it means there is some text here.
//all the removed node are there in the backup
//re insert it anyway you like*
}

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