在ElasticSearch中搜索

Question

我在弹性搜索中遇到问题。在控制台Kibana中，我正在执行此代码，

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="icon-bar" style="float: left; height: 100%; background-color: #1C2336;">
  <div class="activeIconBar iconBarItem" style="border-left: 2px #51B4C7 solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-eye"></i> sada sd a</a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #79AE16 solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-user-o"></i>asasdasd<asdasd/a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #6DC763 solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-info-circle" aria-hidden="true"></i></a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #0574E7 solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-folder-open-o" aria-hidden="true"></i></a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #5285BA solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-calendar"></i></a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #80BCFB solid;"><a onclick="setActiveTab()" class="" href="#"><i></i></a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #FF8402 solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-line-chart"></i></a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #FFAE00 solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-desktop"></i></a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #FFDF61 solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-users"></i></a>
  </div>
  <div class="iconBarItem" style="border-left: 2px #B147E9 solid;"><a onclick="setActiveTab()" class="" href="#"><i class="fa fa-user-times"></i></a>
  </div>
</div>

我有这个结果。

GET bounce_gmd/_search
{
 "query": { "match_phrase": { "date_added": "2017-02-08" } },
  "size": 0,
  "aggs": {
   "date_added": {
     "terms": {
      "field": "bounce_type.keyword"
      }
     }
   }
 }

但是当我从我的laravel项目中跑出来时，我没有这个结果。 我的php代码看起来像这样，

{
 "took": 1,
 "timed_out": false,
 "_shards": {
 "total": 5,
 "successful": 5,
"failed": 0
},
"hits": {
"total": 129812,
"max_score": 0,
"hits": []
},
 ........................... and many more lines.

这里$ index_name ='bounce_gmd'和$ now_time =“2017-02-08”。

但答案是，

我将代码更改为，

$params['index'] = $index_name;
$params['type']  = $index_name;
$params['body']  = $json;
$params['body']['query']['match_phrase']['date_added'] = $now_time;
$params['body']['size']=0;
$params['body']['aggs']['bounce_type']['terms']['field']='bounce_type.keyword';
$response = $client->search($params);

但答案仍然是一样的。我不明白是什么问题。请帮我。

Answer 1

为什么在0上指定大小？它应该有一些价值。您的聚合也可以包含可能的大小（每个aggs应该采用最大可能的选项）。工作查询的一些示例：

{
  "from" : 0,
  "size" : 10,
   "query" : {
    "match" : { 
        "body": 
        {
        "query":"press key handler ",
        "operator":"or",
        "analyzer":"english"
      }
      }
  },
  "aggs" : {
    "category_aggs" : { "terms" : { "field": "category", "size":25}},
    "year_aggs" : { "terms" : { "field": "year", "size":30}},
    "post_type_aggs" : { "terms" : { "field": "post_type", "size":2}}
  }
}