Question

嗨我正在尝试使用子菜单创建动态菜单。我差不多完成了，但循环重复，你可以在输出图像中看到，这不应该发生。错误就像1。水果主菜单正在重复。[2] .fruits子类别正在拆分和显示。

menu.php

$where_array = array('role_id' => $currentRolename , 'active_status' => '1');  //step1
        $table = 'bg_assignment';
        $query = $this->db->where($where_array)->get($table);
        foreach ($query->result() as $perm)
        { 

                $bg = $perm->bg_id;  
                $temp = '1';
                    $where_array2 = array('role_id' => $currentRolename ,  'permission' => '1');            //step2         
                    $table2 = 'role_permission';
                    $query2 = $this->db->where($where_array2)->get($table2);
                            foreach ($query2->result() as $r2)
                    {  
                     $bg_id = $r2->bg_id;

                        $where_array3 = array('bg_id' => $bg_id);                       
                        $table3 = 'bg_forms';

                        $query3 = $this->db->where($where_array3)->get($table3);
                                foreach ($query3->result() as $r3)
                                {

                        $where_array4 = array('phpfile_name' => $r3->phpfile_name);                     
                    $table4 = 'bg_forms';
                    $query4 = $this->db->where($where_array4)->get($table4);
                    foreach ($query4->result() as $r4)
                    {  
                            ?>


                            <li class="treeview <?php echo menu_li_active($r4->category_name); ?>">
                            <a href="#">
                                <i class="fa fa-sitemap"></i>
                            <span>  <?php echo ($r4->category_name); ?></span>
                                <i class="fa fa-angle-left pull-right"></i>
                            </a>    

                                    <ul class="treeview-menu">     
                                        <?php  echo menu_link($r4->controller.'/'.$r4->phpfile_name,    $r4->displayform_name); ?>                                  
                                      </ul>
                    <?php } }?> 
                        </li>
                    </li>

        <?php                                 
        }   
        }  
        ?>

Answer 1

我没有做任何测试，只是在这里提出一些想法，我认为如果你只是在查询中使用内连接会更容易和更清楚。下面的代码可能有语法错误，我没有和你一样的环境来进行测试。

<?php
//Let me just use open query to make this clear. 
$sql_query = '
select rp.bg_id,
       bf.category_name,
       bf.controller,
       bf.phpfile_name,
       bf.displayform_name   
from bg_assignment ba
inner join Role_permission rp
on ba.role_id = rp.role_id
and ba.bg_id = rp.bg_id --You might also want this line
inner join Bg_forms bf
on bg_id = bf.bg_id
where rp.permission = 1
and ba.active_status = 1
order by rp.bg_id, bf.displayform_name
';//I missed this semicolon

//Above sql query will give you two records
//Please test above query in your mysql to see if you can get below two records
/*
bg_id  category_name  controller  phpfile_name     displayform_name
5         Fruits         Product     index            Apple
5         Frutis         Product     sales            Orange
*/

$query = $this->db->query($sql_query);
$result = $query->result_array();

if(count($result) > 0){ // We get records!
  $html = '';
  for($i = 0; $i<count($result); $i++){
        $s = $result[$i];
        //Make the first li no matter what
        if($i === 0){
            $html.= '<li class="treeview">'.menu_li_active($s->category_name);
            $html.= '<a href="#">';
            $html.= '<i class="fa fa-sitemap"></i>';
            $html.= '<span>'.$s->category_name.'</span>';
            $html.= '<i class="fa fa-angle-left pull-right"></i>';
            $html.= '</a>';
            $html.= '</li>';
            $html.= '<ul class="treeview-menu">';
            $html.= menu_link($s->controller.'/'.$s->phpfile_name, $s->displayform_name);
            if(count($result)===1){
                $html.= '</ul>';
            }
        }
        else{
            if($s->category_name === $result[$i-1]->category_name){
                //If current category is the same as previous one, we put them in one tab
              $html.= menu_link($s->controller.'/'.$s->phpfile_name, $s->displayform_name); 
            }
            else{
                //If different, create a new tab
              $html.='</ul>';
              $html.= '<li class="treeview">'.menu_li_active($s->category_name);
              $html.= '<a href="#">';
              $html.= '<i class="fa fa-sitemap"></i>';
              $html.= '<span>'.$s->category_name.'</span>';
              $html.= '<i class="fa fa-angle-left pull-right"></i>';
              $html.= '</a>';
              $html.= '</li>';
              $html.= '<ul class="treeview-menu">';
              $html.= menu_link($s->controller.'/'.$s->phpfile_name, $s->displayform_name);
            }           
        }
    }
  $html.='</li>';
  echo $html;
}
?>

codeigniter动态菜单创建

1 个答案: