Question

这是html

<form action="addadd.php" method="post" enctype="multipart/form-data" name="form1" id="form1">
    <p>
        First Name<br>
        <label for="firstname"></label>
        <input type="text" name="firstname" id="firstname" />
    </p>
    <p>
        Last Name<br>
        <label for="lastname"></label>
        <input type="text" name="lastname" id="lastname" />
    </p>
    <p>
        Mobile<br>
        <label for="mobile"></label>
        <input type="text" name="mobile" id="mobile" />
    </p>
    <p>
        Email<br>
        <label for="email"></label>
        <input type="text" name="email" id="email" />
    </p>
    <p>
        <input type="submit" name="button" id="button" value="Submit" /> 
        <input type="reset" name="button3" id="button3" value="Reset" />
    </p>
</form>

这是php

数据库连接

<?php
$con = mysql_connect("localhost","root","");
if(!$con)
{
die("connection to database failed".mysql_error());
}
$dataselect = mysql_select_db("qoot",$con);
if(!$dataselect)
{
die("Database namelist not selected".mysql_error());
}
?>


<?php 
    $unm = $_SESSION['name']; 
    $fname=$_POST['firstname']; 
    $lname=$_POST['lastname']; 
    $ema=$_POST['email'];
    $mob=$_POST['mobile'];
?>



<?php 
    $qry=mysql_query("INSERT INTO address( firstname, lastname, mobile, email)VALUES('$fname',$lname','$ema','$mob')", $con);
?>

现在问题是这不会在我的数据库中插入任何内容还有什么我可以尝试，以检查出错的地方？更新的数据库连接详细信息

Answer 1

将您的表名address放入反引号

使用mysqli_

  <?php
/start session
session_start();
//establish connection
$con = mysqli_connect("localhost","root","","qoot");
if(!$con)
{
die("connection to database failed".mysqli_error($con));
}
     //read the values from form
    $unm = $_SESSION['name']; 
    $fname=$_POST['firstname']; 
    $lname=$_POST['lastname']; 
    $ema=$_POST['email'];
    $mob=$_POST['mobile'];
?>



<?php 
   //insert to database
    $qry=mysqli_query($con,"INSERT INTO `address` ( firstname, lastname, mobile, email)VALUES('$fname',$lname','$ema','$mob')") or die(mysqli_error($con));
?>

P.S我说你有mysql injection的风险，请点击这里How can I prevent SQL injection in PHP?。你应该使用准备好的陈述来避免任何风险。

表单没有使用mysql

1 个答案: