Question

我有两个字符串数组

string[] oldname = ["arun","jack","tom"];
string[] newname = ["jack","hardy","arun"];

这里我想比较这两个字符串数组来分别得到这些不同的值，如：

oldname = ["tom"];
newname = ["hardy"];

如何实现这些......

Answer 1

string[] oldNameDistinct = oldname.Where(s => !newname.Contains(s)).ToArray();
string[] newNameDistinct = newname.Where(s => !oldname.Contains(s)).ToArray();

Answer 2

让两个数组的定义如下：

 string[] oldname = new[] { "arun", "jack", "tom" };
 string[] newname = new string[] { "jack", "hardy", "arun" };

然后，您可以使用扩展方法.Except来实现您正在寻找的结果。请考虑以下代码和working example

 var distinctInOld = oldname.Except(newname);
 var distinctInNew = newname.Except(oldname);

Answer 3

试试这个：

    string[] oldname = new string[] { "arun", "jack", "tom" };
    string[] newname = new string[] { "jack", "hardy", "arun" };

    List<string> distinctoldname = new List<string>();
    List<string> distinctnewname = new List<string>();

    foreach (string txt in oldname)
    {
       if (Array.IndexOf(newname, txt) == -1)
         distinctoldname.Add(txt);
     }

     foreach (string txt in newname)
     {
        if (Array.IndexOf(oldname, txt) == -1)
          distinctnewname.Add(txt);
     }


   //here you can get both the arrays separately

希望这有帮助：）

Answer 4

string[] oldname = new []{"arun","jack","tom"};
string[] newname = new []{"jack","hardy","arun"};

// use linq to loop through through each list and return values not included in the other list.
var distinctOldName = oldname.Where(o => newname.All(n => n != o));
var distinctNewName = newname.Where(n => oldname.All(o => o != n));

distinctOldName.Dump(); // result is tom
distinctNewName.Dump(); // result is hardy

如何在字符串数组中单独获取不同的值？

4 个答案: