Question

我在这个查询中工作。

$data = RtvReqDet::find()
            ->joinWith(['header', 'rtvCard.serial sn', 'rtvCard.serial.item si', 'rtvCard.item ri' ])
            ->select([
                'header.requested_by as classification',
                'ifnull(sn.no, rtvCard.serial_no) AS serial',
                'ifnull(si.no, ri.no) AS item',
                'ifnull(si.uom, ri.uom) AS uom',
                'COUNT(ifnull(sn.no, rtvCard.serial_no)) AS qty',
            ])
            ->where(['rtv_spare_parts_requisition_id' => $record->id ])
            ->groupBy(['serial'])->all();

它在Windows上工作。但是没有在Linux上工作并且出现这个错误：

Exception 'yii\base\InvalidParamException' with message 'app\models\RtvCard has no relation named "serial AS sn".'

我试着用Linux完全降低我的php版本和mysql版本。但我仍然可以在我的窗户上进行交易。所以它与php和mysql版本没有任何冲突。你认为这有什么不对？

这是rtvCard模型。这是我以前和我合作过的同事定制的。我在本次讨论中删除了一些我认为不需要的关系。

<?php

namespace app\models;

use app\components\ActiveRecord;
use app\components\FieldException;
use yii\base\Exception;

class RtvCard extends ActiveRecord  {

    static function tableName() {
        return "rtv_card";
    }

    static function objectName()    {
        return "rtv card";
    }

    // RELATIONS
    function getCustomer()  {
        return $this->hasOne(Customer::className(), [ "id" => "customer_id" ])->from([ "customer" => Customer::tableName() ]);
    }
    function getSerial()    {
        return $this->hasOne(SerialNumbers::className(), [ "id" => "serial_id" ])->from([ "serial" => SerialNumbers::tableName() ]);
    }
    function getItem()  {
        return $this->hasOne(Items::className(), [ "id" => "item_id" ])->from([ "item" => Items::tableName() ]);
    }
    function getTransfer()  {
        return $this->hasOne(RtvTransferDetail::className(), [ "rtv_card_id" => "id" ])->from([ "transfer" => RtvTransferDetail::tableName() ]);
    }

    // USED FOR ERROR MESSAGES
    static $attributeLabels = [
        "id" => "ID",
        "no" => "RTV No",
        "item_id" => "Item",
        "serial_id" => "Serial no.",
        "defect_id" => "Defect",
        "description" => "Complaints",
        "date_received" => "Date received",
        "received_by" => "Received by",
        "customer_id" => "Dealer",
        "reference_no" => "Reference no.",
        "tag" => "Tag",
        "technician_id" => "Technician",
        "warehouse" => "Warehouse",
    ];
    // FIELD NAMES IN VIEW IF NOT THE SAME WITH ATTRIBUTE
    // USE STATIC::GET-FIELD($ATTRIBUTE-NAME)
    // ATTRIBUTE NAME SHOULD BE THE TABLE ATTRIBUTES ITSELF ( NOT THE FIELD NAME IN VIEWS )
    // ATTRIBUTE NAME => FIELD NAME
    static $attributeFields = [
        "item_id" => "item",
        "serial_id" => "serial",
        "defect_id" => "defect",
        "customer_id" => "dealer",
        "received_by" => "received-by",
        "date_received" => "received-date",
        "reference_no" => "reference-no",
        "open_serial_id_no" => "no",
        "open_serial_id_item" => "item",
        "technician_id" => "technician",
    ];

Answer 1

从Yii 2.0.7开始，关系别名的快捷方式是'rtvCard.serial sn' ~~而不是'rtvCard.serial AS sn'~~ （来自Bizley的评论{{1也有效）

来自docs：

如果在连接嵌套关系时需要中间表的别名，例如AS，您需要嵌套$query->joinWith(['orders.product'])次调用，如下例所示：
joinWith

所以在你的情况下：

$query->joinWith(['orders o' => function($q) {
    $q->joinWith('product p');
}])
->where('o.amount > 100');

Answer 2

在两个安装中你的版本都相同是更好的...但是请确保你的文件正确适用于UpperCase ..

RtvCard.php

..因为Windows文件名不区分大小写，但linux是区分大小写的。还要检查控制器中的use classname .....请参阅正确的区分大小写的名称

在Linux中的joinWith（YII2）中添加别名不起作用

2 个答案: