我有多个具有相同选项且相互排斥的选择框。例如,如果选择框A并且选择框B有选项1,选项2和选项3,那么如果我为选择框A选择选项1,那么它应该不可用在选择框B
上我的演示
<select name="select" class="alert_type">
<option selected disabled>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
<select name="select" class="alert_type">
<option selected disabled>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
<select name="select" class="alert_type">
<option selected disabled>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
$('.alert_type').change(function() {
var selected_value=$(this).val();
$(".alert_type option[value='" + selected_value + "']").not(this.selectedOptions[0]).hide();
});
但我想将第一个选项作为例外,<option value="">Select below</option>
,因为我需要灵活地恢复所有选项
您可以在下面的小提琴中看到,如果我从选择框1中选择选项1,则从选项3中“选择下方”也会被删除,我想将其置于例外 小提琴 https://jsfiddle.net/timus2001/rbuyk7na/3/
当我尝试
时$(".alert_type option").show();
答案 0 :(得分:2)
确定。让我看看我这次能不能找到你:
$('.alert_type').change(function() {
var selected_values = [],
iteration;
$(".alert_type option").show();
$(".alert_type").each(function(){
iteration = $(this).find('option:selected').val();
if ( iteration !== "" ) {
selected_values.push( iteration );
}
})
for ( var i = 0; i < selected_values.length; i++ ) {
$(".alert_type option[value='"+ selected_values[i] +"']").hide();
}
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<select name="select" class="alert_type">
<option selected>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
<select name="select" class="alert_type">
<option selected>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
<select name="select" class="alert_type">
<option selected>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
&#13;
答案 1 :(得分:0)
$('select.alert_type').on('change keyup',function() {
var val = $(this).val();
$('select.alert_type option').prop('disabled',false);
$(this).siblings().find('option[value='+val+']').prop('disabled',true);
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select name="select" class="alert_type">
<option selected disabled>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
<select name="select" class="alert_type">
<option selected disabled>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
<select name="select" class="alert_type">
<option selected disabled>Select below</option>
<option value="1">option1</option>
<option value="2">option2</option>
<option value="3">option3</option>
<option value="4">option4</option>
</select>
&#13;
祝你好运:D