Question

如何使用HttpClient发送文件和表单数据？

我有两种发送文件或表单数据的方法。但我想像HTML表单一样发送它们。我怎样才能做到这一点？谢谢。

这是我的代码：

if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
    var client = new HttpClient();
    var requestContent = new MultipartFormDataContent();
    filename = openFileDialog1.FileName;
    array = File.ReadAllBytes(filename);
    var imageContent = new ByteArrayContent(array);
    imageContent.Headers.ContentType = MediaTypeHeaderValue.Parse("audio/*");
    requestContent.Add(imageContent, "audio", "audio.wav");
    var values = new Dictionary<string, string>
    {
        { "token", "b53b99534a137a71513548091271c44c" },
    };
    var content = new FormUrlEncodedContent(values);
    requestContent.Add(content);
    var response = await client.PostAsync("localhost", requestContent);
    var responseString = await response.Content.ReadAsStringAsync();
    txtbox.Text = responseString.ToString();
}

Answer 1

此处的代码我用来发布表单信息和csv文件

using (var httpClient = new HttpClient())
{
    var surveyBytes = ConvertToByteArray(surveyResponse);

    httpClient.DefaultRequestHeaders.Add("X-API-TOKEN", _apiToken);
    httpClient.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

    var byteArrayContent =   new ByteArrayContent(surveyBytes);
    byteArrayContent.Headers.ContentType = MediaTypeHeaderValue.Parse("text/csv");

    var response = await httpClient.PostAsync(_importUrl, new MultipartFormDataContent
    {
        {new StringContent(surveyId), "\"surveyId\""},
        {byteArrayContent, "\"file\"", "\"feedback.csv\""}
    });

    return response;
}

这是针对.net 4.5的。

注意\＆＃34;在MultipartFormDataContent中。 MultipartFormDataContent中有一个bug。

在4.5.1中，MultipartFormDataContent用正确的引号包装数据。

更新：此漏洞的链接不再有效，因为已退休的Microsoft Connect。

Answer 2

这是代码，我正在使用一种方法将文件和数据从控制台发送到API

 static async Task uploaddocAsync()
                    {
                        MultipartFormDataContent form = new MultipartFormDataContent();
                        Dictionary<string, string> parameters = new Dictionary<string, string>();
                        //parameters.Add("username", user.Username);
                        //parameters.Add("FullName", FullName);
                        HttpContent DictionaryItems = new FormUrlEncodedContent(parameters);
                        form.Add(DictionaryItems, "model");

                        try
                        {
                            var stream = new FileStream(@"D:\10th.jpeg", FileMode.Open);
                            HttpClient client = new HttpClient();
                            client.BaseAddress = new Uri(@"http:\\xyz.in");

                            HttpContent content = new StringContent("");
                            content.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
                            {
                                Name = "uploadedFile1",
                                FileName = "uploadedFile1"
                            };
                            content = new StreamContent(stream);
                            form.Add(content, "uploadedFile1"); 

                            client.DefaultRequestHeaders.Add("Authorization", "Bearer eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.dsfdsfdsfdsfsdfkhjhjkhjk.vD056hXETFMXYxOaLZRwV7Ny1vj-tZySAWq6oybBr2w");

                            var response = client.PostAsync(@"\api\UploadDocuments\", form).Result;
                            var k = response.Content.ReadAsStringAsync().Result;
                        }
                        catch (Exception ex)
                        {


                        }
                    }

如何在C＃中使用HttpClient发送文件和表单数据

2 个答案: