如何在zend字面内逃避事物?

时间:2017-02-13 17:47:08

标签: php mysql search zend-framework zend-framework2

我正在创建一个高级搜索,并希望通过将它们添加到数组中来循环查询:

private $searchFields = [
    'as_first_name'                  => 'users.first_name like "%VALUE%"',
    'as_last_name'                   => 'users.last_name like "%VALUE%"',
    'as_payment_history_invoice_num' => 'users.user_id = (SELECT user_id from payment_history where payment_history.invoice_number = "VALUE" LIMIT 1)',
    'as_building_num'                => 'property_units.building_number like "%VALUE%"',
    'as_residents_email'             => 'users.email like "%VALUE%"',
    'as_property_name'               => 'property.name like "%VALUE%"',
    'as_phone_num'                   => 'REPLACE(REPLACE(REPLACE(REPLACE(users.phone, " ", ""), "(", ""), ")", ""), "-", "") = "VALUE"',
    'as_unit_num'                    => 'property_units.unit_number = "VALUE"',
    'as_account_status'              => 'user_status.status_name = "VALUE"'
];

所以在搜索中我做了类似的事情。

if (array_key_exists($key, $this->searchFields)) {

    $form->get($key)->setValue($val);
    $where->NEST->literal(str_replace('VALUE', urldecode($val), $this->searchFields[$key]))->UNNEST;
}

但问题是我没有逃避任何事情。不好。我如何使用相同的结构,但也可以逃避。

2 个答案:

答案 0 :(得分:6)

Literal谓词适用于没有占位符的情况。 您应该使用Expression谓词。

private $searchFields = [
    'as_first_name'                  => 'users.first_name like "?"',
    'as_last_name'                   => 'users.last_name like "?"',
    'as_payment_history_invoice_num' => 'users.user_id = (SELECT user_id from payment_history where payment_history.invoice_number = "?" LIMIT 1)',
    'as_building_num'                => 'property_units.building_number like "?"',
    'as_residents_email'             => 'users.email like "?"',
    'as_property_name'               => 'property.name like "?"',
    'as_phone_num'                   => 'REPLACE(REPLACE(REPLACE(REPLACE(users.phone, " ", ""), "(", ""), ")", ""), "-", "") = "?"',
    'as_unit_num'                    => 'property_units.unit_number = "?"',
    'as_account_status'              => 'user_status.status_name = "?"'
];

zend-form值应该已经被解码,因此不需要urldecode

if (array_key_exists($key, $this->searchFields)) {

    $form->get($key)->setValue($val);
    $where->NEST->expression($this->searchFields[$key], $val)->UNNEST;
}

我很长一段时间没有使用zend-db,请确保检查此代码是否实际产生了您需要的查询。

答案 1 :(得分:0)

您不应该使用urldecode;它应该在你到达之前解码。听起来NEST对于这种情况可能过于花哨。

foreach (...)
{
    $val = ...;  // Get the raw value from the form field ($_POST[...] or whatever)
    $mval = addslashes($val);
    $sf = $this->searchFields[...];
    $msf = str_replace('VALUE', $mval, $sf);
    ... $msf ...
}

mysqli_real_escape_str会比addslashes好,但你需要拥有mysql连接对象;你有吗?