pandas Dataframe.hist直方图，seaborn风格

Question

我有一个数据帧，即

df = pd.DataFrame([1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10,1,2,3,4,5,6,7,8,9,10])

使用hist（）产生例如：

df.hist()

这是准确的，但在视觉上并不令人愉快，尽管可以改进，例如

df.hist(ec='black')

默认情况下seaborn提供的内容很远（编辑：Seaborn似乎进行插值并给出描述直方图分布的直线）。另一方面，seaborn默认不会给我＆＃34;权利＆＃34; （=我想要/期望;））没有箱子和y轴，例如：

import seaborn as sns
sns.distplot(df.values);
plt.show()

有没有办法让panda的hist命令在熊猫中重现seaborn的风格？